A professional basketball star who had a reputation for being a poor free throw shooter made 5210 of the 9721 free throws that he attempted, for a success ratio of 0.536. A simulation was developed to generate random numbers between 1 and 1000. An outcome of 1 through 536 was considered to be a free throw that is made, and an outcome of 537 through 1000 was considered to be a free throw that is missed. The list below shows the results for five generated numbers where 1 represents a free throw that was made and 0 represents a free throw that was missed. Complete parts (a) and (b). a. Is the proportion of successful free throws P from the simulation reasonably close to the value of 0.536? (Hint: A proportion is said to be "reasonably close" if it is within the given success ratio ± the probability of a single event.) O Yes, P is reasonably close to the value of 0.536. No, P is not reasonably close to the value of 0.536. 1 1 1 0 0 b. The simulation was conducted 10 times to generate five results R1, R2, R3, R4 and R5 each time, as shown in the table below. Determine the proportion of successful free throws P in each case. Case R1 R2 R3 R4 R5 P 1 1 1 1 2 1 1 1 3 1 1 1 4 1 1 1 1 1 1 1 1 7 1 1 1 8 1 1 9 1 1 1 10 1 1 1 1 (Do not round.)

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a. Is the proportion of successful free throws P from the simulation reasonably
close to the value of 0.536? (Hint: A proportion is said to be "reasonably close" if it
is within the given success ratio + the probability of a single event.)
A professional basketball star who had a reputation for being a poor free throw
shooter made 5210 of the 9721 free throws that he attempted, for a success ratio
of 0.536. A simulation was developed to generate random numbers between 1 and
1000. An outcome of 1 through 536 was considered to be a free throw that is
made, and an outcome of 537 through 1000 was considered to be a free throw that
is missed. The list below shows the results for five generated numbers where 1
represents a free throw that was made and 0 represents a free throw that was
missed. Complete parts (a) and (b).
Yes, P is reasonably close to the value of 0.536.
No, P is not reasonably close to the value of 0.536.
1 1 1 0 0
b. The simulation was conducted 10 times to generate five results R1, R2, R3, R4
and R5 each time, as shown in the table below. Determine the proportion of
successful free throws P in each case.
Case
R1
R2
R3
R4
R5
1
1
1
1
1
1
1
3
1
1
4
1
1
1
5
1
1
1
1
1
1
7
1
1
1
8
1
1
1
1
1.
10
1
1
1
(Do not round.)
P OON OOOD OON
Transcribed Image Text:a. Is the proportion of successful free throws P from the simulation reasonably close to the value of 0.536? (Hint: A proportion is said to be "reasonably close" if it is within the given success ratio + the probability of a single event.) A professional basketball star who had a reputation for being a poor free throw shooter made 5210 of the 9721 free throws that he attempted, for a success ratio of 0.536. A simulation was developed to generate random numbers between 1 and 1000. An outcome of 1 through 536 was considered to be a free throw that is made, and an outcome of 537 through 1000 was considered to be a free throw that is missed. The list below shows the results for five generated numbers where 1 represents a free throw that was made and 0 represents a free throw that was missed. Complete parts (a) and (b). Yes, P is reasonably close to the value of 0.536. No, P is not reasonably close to the value of 0.536. 1 1 1 0 0 b. The simulation was conducted 10 times to generate five results R1, R2, R3, R4 and R5 each time, as shown in the table below. Determine the proportion of successful free throws P in each case. Case R1 R2 R3 R4 R5 1 1 1 1 1 1 1 3 1 1 4 1 1 1 5 1 1 1 1 1 1 7 1 1 1 8 1 1 1 1 1. 10 1 1 1 (Do not round.) P OON OOOD OON
Expert Solution
Step 1 Proportion calculation

For case one the required proportion P is calculated as:

P=Number of free throws that were made successfullyTotal number of free throws made=35=0.6

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