A product of the following reaction would be Benzene 1/2 l2 + HNO3 O 1,3-Diiodobenzene O lodobenzene O 1,2-Diiodobenzene O 1,1-Dichloro-iodobenzene O 1,4-Diiodobenzene
A product of the following reaction would be Benzene 1/2 l2 + HNO3 O 1,3-Diiodobenzene O lodobenzene O 1,2-Diiodobenzene O 1,1-Dichloro-iodobenzene O 1,4-Diiodobenzene
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A product of the following reaction would be
Benzene
1/2 12 + HNO3
O 1,3-Diiodobenzene
O. lodobenzene
O 1,2-Diiodobenzene
O 1,1-Dichloro-iodobenzene
O 1,4-Diiodobenzene
Expert Solution

Step 1
Halogenation of benzene takes place by an electrophilic aromatic substitution reaction mechanism. Chlorination and bromination of benzene take place in the presence of Lewis acid catalyst. The iodination of benzene cannot proceed in the presence of Lewis acid catalyst because the bond energy change in the iodination reaction is unfavorable.
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