A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed?
A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Calculating Angular Speed of a Roller
**Problem Statement:**
A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed?
**Step-by-Step Solution:**
1. **Convert Diameter to Radius:**
- Diameter of the roller \( D = 17 \) inches
- Radius \( r = \frac{D}{2} = \frac{17}{2} = 8.5 \) inches
2. **Convert Radius to Feet:**
- Since 1 foot = 12 inches, then:
\[
r = \frac{8.5}{12} \text{ feet} \approx 0.7083 \text{ feet}
\]
3. **Determine Linear Speed:**
- Linear speed \( v = 85 \) feet per second
4. **Use the Angular Speed Formula:**
- Angular speed \( \omega \) is given by:
\[
\omega = \frac{v}{r}
\]
- Plugging in the values:
\[
\omega = \frac{85 \text{ feet/second}}{0.7083 \text{ feet}} \approx 120 \text{ radians/second}
\]
5. **Round Answer:**
- Angular speed to the nearest hundredth:
\[
\omega \approx 120.00 \text{ radians/second}
\]
**Result:**
The roller's angular speed is \( \boxed{120.00} \) radians per second (rounded to the nearest hundredth).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87bb6fa2-16f6-449b-8672-e576ef2a7d16%2F93da1ebb-9edc-4fbb-a885-0e9b7e7b5cd3%2Fu6aopbq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculating Angular Speed of a Roller
**Problem Statement:**
A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed?
**Step-by-Step Solution:**
1. **Convert Diameter to Radius:**
- Diameter of the roller \( D = 17 \) inches
- Radius \( r = \frac{D}{2} = \frac{17}{2} = 8.5 \) inches
2. **Convert Radius to Feet:**
- Since 1 foot = 12 inches, then:
\[
r = \frac{8.5}{12} \text{ feet} \approx 0.7083 \text{ feet}
\]
3. **Determine Linear Speed:**
- Linear speed \( v = 85 \) feet per second
4. **Use the Angular Speed Formula:**
- Angular speed \( \omega \) is given by:
\[
\omega = \frac{v}{r}
\]
- Plugging in the values:
\[
\omega = \frac{85 \text{ feet/second}}{0.7083 \text{ feet}} \approx 120 \text{ radians/second}
\]
5. **Round Answer:**
- Angular speed to the nearest hundredth:
\[
\omega \approx 120.00 \text{ radians/second}
\]
**Result:**
The roller's angular speed is \( \boxed{120.00} \) radians per second (rounded to the nearest hundredth).
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