A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed?

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Chapter7: Rotational Motion And The Law Of Gravity
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### Calculating Angular Speed of a Roller

**Problem Statement:**
A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed?

**Step-by-Step Solution:**

1. **Convert Diameter to Radius:**
   - Diameter of the roller \( D = 17 \) inches
   - Radius \( r = \frac{D}{2} = \frac{17}{2} = 8.5 \) inches

2. **Convert Radius to Feet:**
   - Since 1 foot = 12 inches, then:
     \[
     r = \frac{8.5}{12} \text{ feet} \approx 0.7083 \text{ feet}
     \]

3. **Determine Linear Speed:**
   - Linear speed \( v = 85 \) feet per second

4. **Use the Angular Speed Formula:**
   - Angular speed \( \omega \) is given by:
     \[
     \omega = \frac{v}{r}
     \]
   - Plugging in the values:
     \[
     \omega = \frac{85 \text{ feet/second}}{0.7083 \text{ feet}} \approx 120 \text{ radians/second}
     \]

5. **Round Answer:**
   - Angular speed to the nearest hundredth:
     \[
     \omega \approx 120.00 \text{ radians/second}
     \]

**Result:**
The roller's angular speed is \( \boxed{120.00} \) radians per second (rounded to the nearest hundredth).
Transcribed Image Text:### Calculating Angular Speed of a Roller **Problem Statement:** A printing press has a roller 17 inches in diameter. A point on the roller's surface moves at a speed of 85 feet per second. What is the roller's angular speed? **Step-by-Step Solution:** 1. **Convert Diameter to Radius:** - Diameter of the roller \( D = 17 \) inches - Radius \( r = \frac{D}{2} = \frac{17}{2} = 8.5 \) inches 2. **Convert Radius to Feet:** - Since 1 foot = 12 inches, then: \[ r = \frac{8.5}{12} \text{ feet} \approx 0.7083 \text{ feet} \] 3. **Determine Linear Speed:** - Linear speed \( v = 85 \) feet per second 4. **Use the Angular Speed Formula:** - Angular speed \( \omega \) is given by: \[ \omega = \frac{v}{r} \] - Plugging in the values: \[ \omega = \frac{85 \text{ feet/second}}{0.7083 \text{ feet}} \approx 120 \text{ radians/second} \] 5. **Round Answer:** - Angular speed to the nearest hundredth: \[ \omega \approx 120.00 \text{ radians/second} \] **Result:** The roller's angular speed is \( \boxed{120.00} \) radians per second (rounded to the nearest hundredth).
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