A pressure difference of 2.40 x 10 Pa is used to inject a sample onto a 64.2 cm long capillary that has a diameter of 65.0 um. Assuming the viscosity of the sample is 0.00106 kg/(m-s), how much time is required to inject a sample that is 2.76% of the length of the capillary? I= 8.3 x106
A pressure difference of 2.40 x 10 Pa is used to inject a sample onto a 64.2 cm long capillary that has a diameter of 65.0 um. Assuming the viscosity of the sample is 0.00106 kg/(m-s), how much time is required to inject a sample that is 2.76% of the length of the capillary? I= 8.3 x106
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:A pressure difference of 2.40 x 10 Pa is used to inject a sample onto a 64.2 cm long capillary that has a diameter of 65.0 µm.
Assuming the viscosity of the sample is 0.00106 kg/(m-s), how much time is required to inject a sample that is 2.76% of the
length of the capillary?
1=
8.3 x106
Transcribed Image Text:K
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The volume (V) of the injected sample
using hydrodynamic injection is given
by the equation
V =
ΔΡmdt
128nLt
where AP is the pressure difference, d
is the diameter of the capillary, it is the
injection time, n is the viscosity of the
sample, and L, is the length of the
capillary. Rearrange the equation to
solve for the injection time.
Assuming the sample plug is
cylindrical, the volume is determined
using the equation
V = r² h
X
where r is the radius of the plug, which
is equal to the radius of the capillary,
and h is the height or length of the
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