A precipitate of PbI2 is formed when 5 mL of 0.012 M Pb(NO3)2 is added to 5 mL of 0.030 M KI. It was found experimentally that the final concentration of I- in the 10 mL solution after equilibrium was 8 x 10-3 M a) How many moles of Pb2+ are originally in the solution? b) How many moles of I- are originally present? c) How many moles of I- remained in solution after equilibrium?
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
A precipitate of PbI2 is formed when 5 mL of 0.012 M Pb(NO3)2 is added to 5 mL of 0.030 M KI.
It was found experimentally that the final concentration of I- in the 10 mL solution after equilibrium was 8 x 10-3 M
a) How many moles of Pb2+ are originally in the solution?
b) How many moles of I- are originally present?
c) How many moles of I- remained in solution after equilibrium?
d) How many moles of I- precipitated?
e) How many moles of PbI2 precipitated?
f) How many moles of PbI2 remain in solution at equilibrium?
g) What is [Pb2+] at equilibrium?
h) What is Ksp for the formation of PbI2 ?
Since you have asked a question with multiple subparts, we will answer only 3 subparts for you. In order to get other subparts answered, kindly repost complete question, specifying the subparts to be answered.
Trending now
This is a popular solution!
Step by step
Solved in 4 steps