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(a) Power factor angle (b) Total current (c) Current of the capacitor (d) Value of the capacitance reactance (-jXc=_ (e) Draw circuit (shown below) (f) Equations used and units (g) Capacitor size Found in class: Resistor current=69.44 A Inductor current=-j166.7 A Given: V=72/0°KV R= 103.68 2 jx=43.22 www R JX P-500kW Pf= 0.95 :-jxc

(a) Power factor angle (b) Total current (c) Current of the capacitor (d) Value of the capacitance reactance (-jXc=_ (e) Draw circuit (shown below) (f) Equations used and units (g) Capacitor size Found in class: Resistor current=69.44 A Inductor current=-j166.7 A Given: V=72/0°KV R= 103.68 2 jx=43.22 www R JX P-500kW Pf= 0.95 :-jxc

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Snow: (a) Power factor angle (b) Total current (c) Current of the capacitor (d) Value of the capacitance reactance (-jxc= (e) Draw circuit (shown below) (f) Equations used and units (g) Capacitor size Found in class: Resistor current=69.44 A Inductor current=-j166.7 A Given: V=72/0°KV R= 103.682 jx=43.252 R JX P-500kW Pf= 0.95 -JXc
Transcribed Image Text:Snow: (a) Power factor angle (b) Total current (c) Current of the capacitor (d) Value of the capacitance reactance (-jxc= (e) Draw circuit (shown below) (f) Equations used and units (g) Capacitor size Found in class: Resistor current=69.44 A Inductor current=-j166.7 A Given: V=72/0°KV R= 103.682 jx=43.252 R JX P-500kW Pf= 0.95 -JXc
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