A potential difference of 0.8 V is maintained between the ends of a metal wire of length 1.0 m. The number density of free electrons in the metal is &8.0 × 1028 per m' and the electrical conductivity of the metal is 6.4 x 10' 2 m. Find the drift speed of electrons.
A potential difference of 0.8 V is maintained between the ends of a metal wire of length 1.0 m. The number density of free electrons in the metal is &8.0 × 1028 per m' and the electrical conductivity of the metal is 6.4 x 10' 2 m. Find the drift speed of electrons.
Related questions
Question

Transcribed Image Text:A potential difference of 0.8 V is maintained between
the ends of a metal wire of length 1.0 m. The number
density of free electrons in the metal is 8.0 × 1028
per m' and the electrical conductivity of the metal is
6.4 x 10' 2 ml. Find the drift speed of electrons.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
