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A positron with laboratory energy 50 Ge + in a lead target to produce μμ¯ pairs. If given by σ = 4ла² ħ²c²/3(Ecm)², calcu The density of lead is p = 1.14 × 104 kg 1

A positron with laboratory energy 50 Ge + in a lead target to produce μμ¯ pairs. If given by σ = 4ла² ħ²c²/3(Ecm)², calcu The density of lead is p = 1.14 × 104 kg 1

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+ A positron with laboratory energy 50 GeV interacts with the atomic electrons in a lead target to produce µμ¯ pairs. If the cross-section for this process is given by o = 4ла² ħ²²/3(ECM)², calculate the positron's interaction length. The density of lead is p = 1.14 × 104 kg m¯ -3
Transcribed Image Text:+ A positron with laboratory energy 50 GeV interacts with the atomic electrons in a lead target to produce µμ¯ pairs. If the cross-section for this process is given by o = 4ла² ħ²²/3(ECM)², calculate the positron's interaction length. The density of lead is p = 1.14 × 104 kg m¯ -3
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