A population of values has a normal distribution withrandom sample of size n = 107.= 197.2 and σ = 26.5. You intend to draw aFind the probability that a sample of size n = 107 is randomly selected with a mean less than 195.7.P(M < 195.7) =Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. A population of values has a normal distribution with μ = 227.3 and σ = 75.1. You intend to draw arandom sample of size n = 11.Find the probability that a single randomly selected value is between 157.1 and 182.P(157.1 < X < 182) ==Find the probability that a sample of size n182.P(157.1 < M < 182) =11 is randomly selected with a mean between 157.1 andEnter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

A population of values has a normal distribution with μ=197.2 and σ=26.5A population of values has a…

Answered: A population of values has a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the Z- Statistic, for a random sample of size 18 from a normal distribution with σ=3 produced a sample mean of 4.4 with a population mean =5.9. Please only find Z statistics. Type the number only no variable!
A distribution of values is normal with a mean of 31.1 and a standard deviation of 27.8. Find P38, which is the score separating the bottom 38% from the top 62%. P38 Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z- scores rounded to 3 decimal places are accepted.
Q3: PVC pipe is manufactured with a mean diameter of 1.01 inch and a standard deviation of 0.003 inch. Find the probability that a random sample of n = 9 sections of pipe will have a sample mean diameter greater than 1.009 inch and less than 1.012 inch. (2000
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A population of values has a normal distribution with μ=74.1μ=74.1 and σ=17.3σ=17.3. A random sample of size n=73n=73 is drawn. Find the probability that a sample of size n=73n=73 is randomly selected with a mean greater than 78.4. Round your answer to four decimal places. P(M>78.4)=P(M>78.4)=
The percent of fat calories that a person consumes each day is normally distributed with a mean of about 35 and a standard deviation of about ten. Suppose that 9 individuals are randomly chosen. Let X = average percent of fat calories. For the group of 9, find the probability that the average percent of fat calories consumed is more than six. (Round your answer to four decimal places.)
Q3: PVC pipe is manufactured with a mean diameter of 1.01 inch and a standard deviation of 0.003 inch. Find the probability that a random sample of n = 9 sections of pipe will have a sample mean diameter greater than 1.009 inch and less than 1.012 inch. (2000
The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces. Suppose that you draw a random sample of 42 cans. Parti) Suppose the number of cans drawn is doubled. How will the standard deviation sample mean weight change? A. It will decrease by a factor of √2. B. It will increase by a factor of √2. C. It will increase by a factor of 2. D. It will decrease by a factor of 2. E. It will remain unchanged. Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change? ▸ A. It will increase by a factor of √2. B. It will decrease by a factor of 2. C. It will increase by a factor of 2. D. It will decrease by a factor of √2. E. It will remain unchanged. Part iii) Consider the statement: The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal." A. It…
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The mean weight of all Goliath grouper caught on the Treasure coast is 367 pounds, with a standard deviation of 33 pounds. Suppose a random sample of 32 Goliath Grouper from the Treasure Coast are caught and weighed. Determine the probability that the average weight of the sample of 32 Goliath Grouper is within 7 pounds of the average weight of all Goliath Grouper caught on the Treasure Coast. Round the solution to four decimal places , if necessary .
A population of values has a normal distribution with mean= 107.9 and sd= 99.9. You intend to draw a random sample of size n = 100. Find P11, Which is the mean separating the bottom 11% means from the top 89% means. P11 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

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