A population of values has a normal distribution with μ=202.1μ=202.1 and σ=24σ=24. You intend to draw a random sample of size n=64n=64. a.) Find the probability that a single randomly selected value is between 204.5 and 205.1. P(204.5 < X < 205.1) = b.) Find the probability that a sample of size n=64n=64 is randomly selected with a mean between 204.5 and 205.1. P(204.5 < M < 205.1) = round 4 decimal places
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A population of values has a
a.) Find the probability that a single randomly selected value is between 204.5 and 205.1.
P(204.5 < X < 205.1) =
b.) Find the probability that a sample of size n=64n=64 is randomly selected with a mean between 204.5 and 205.1.
P(204.5 < M < 205.1) =
round 4 decimal places
Step by step
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- Question 8. This question is similar to Exercise 11 on page 363 of your textbook. Let t be a t-random variable. P(ta) = 0.05 and 65 degrees of freedom. Use Excel function =t.inv to find a. ii. Use Excel function =t.dist to find P(t 2.16) with df =23 This is a fill-in-blank question. Do not show your work. Write your answer with the format of #.###, #.####, #.####. The first number is for (i), the second number is for (ii), and so on.Travis does research with a marine biology research team. His job is to catch lobsters, weigh them, tag them, and return them to the water. Over the years, the team has determined that the average weight in pounds of the lobsters caught at a particular location was µ = 2.1 lbs. with a σ of 1.8 lbs. As part of an annual survey, Travis catches 27 lobsters with a mean of 3.1 lbs. Is he correct in assuming that the lobsters he caught are significantly heavier that those usually found in that location? Please use α = .05 and a two-tailed test.A company wants to determine whether it's consumer product ratings (0-10) have changed from last year to this year. The table below shows the company's product ratings from 8 consumers for last year and this year. At a=0.05, is there enough evidence to conclude that the ratings have changed? Assume the samples are random and dependent, and the population is normally distributed. Complete parts A-F.
- residence), the average 220V is measured and the standard deviation is co ated as 4V. What is the least probability that the voltage of a randomly selected When the phase-neutral voltage value of the consumers fed from a transformer is measured from the vault point (you can assume the entry point to the consumer is between 202V and 232V? G0 100555- g160100555870479447 B A 60 100555- 14/25 3/4 60100555-987047 g160100555 - 9870479447 15/16 g160 0555 -987 8/9 60100555- g160100555 - 9870479447 TO 12/13 60100555-987047 g160100555 -987047944 g160100555 - 9870479447 g160100555 - 987047944 60100555-987047 g160100555 - 9870479447 g160100555 -987047944 60100555-9870475 g160100555 - 9870479447 g160100555 -987047944 60100555-9 g160100555 - 987047944 g160100555 - 987047944 g160100555 - 9 g160100555 987047944 g160100555 - 9Statistics QuestionIf z is a standard normal random variable and P(-zySuppose in a local Kindergarten through 12th grade (K -12) school district, 49% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. a. Find the mean and the standard deviation of X of B(144, 0.49). Round off to 4 decimal places. O = b. Now approximate X of B(144, 0.49) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y - N( c. Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(A population of values has a normal distribution with μ=14.7μ=14.7 and σ=31.3σ=31.3. You intend to draw a random sample of size n=20n=20.Find the probability that a single randomly selected value is between 30.1 and 34.3.P(30.1 < X < 34.3) = Find the probability that a sample of size n=20n=20 is randomly selected with a mean between 30.1 and 34.3.P(30.1 < M < 34.3) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.Suppose in a local Kindergarten through 12th grade (K -12) school district, 49% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. a. Find the mean and the standard deviation of X of B(144, 0.49). Round off to 4 decimal places. O = b. Now approximate X of B(144, 0.49) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y - N( c. Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(Let x be a random variable that represents blood glucose level after a 12-hour fast. Let y be a random variable representing blood glucose level 1 hour after drinking sugar water (after the 12-hour fast). Units are in milligrams per 10 milliliters (mg/10 ml). A random sample of eight adults gave the following information. Σχ - 64.2; Σ ? = 528.24; Ey = 90.4; Ey² = 1063.88; Exy = 741.77 6.2 8.6 7.0 7.5 8.3 6.9 10.0 9.7 y 9.7 10.3 10.9 11.5 14.2 7.0 14.6 12.2 Find the equation of the least-squares line. (Round your answers to three decimal places.) Find the sample correlation coefficient r and the sample coefficient of determination r. (Round your answers to three decimal places.) r = 2 = If x = 7.0, use the least-squares line to predict y. (Round your answer to two decimal places.) y = Find an 80% confidence interval for your prediction. (Round your answers to two decimal places.) lower limit mg/10 ml upper limit mg/10 ml Use level of significance 1% and test the claim that the…A population of values has a normal distribution with μ=99.6μ=99.6 and σ=35.1σ=35.1. You intend to draw a random sample of size n=84n=84.Find the probability that a single randomly selected value is between 98.5 and 100.7.P(98.5 < X < 100.7) = Find the probability that a sample of size n=84n=84 is randomly selected with a mean between 98.5 and 100.7.P(98.5 < ¯xx¯ < 100.7) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.A population of values has a normal distribution with μ=89μ=89 and σ=53.8σ=53.8. A random sample of size n=14n=14 is drawn. Find the probability that a single randomly selected value is greater than 70.3. Round your answer to four decimal places. P(X>70.3)=P(X>70.3)= Find the probability that a sample of size n=14n=14 is randomly selected with a mean greater than 70.3. Round your answer to four decimal places. 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