A population of endangered salmon, S(t), starts out with 100 fish and decreases at a rate proportional to 0.02 times the number of fish present each year. A population of flounder, F(t), also starts out with a population of 100 fish and decreases at a rate proportional to 0.01 times the number of fish present each year. What is the equation which describes the difference between the number of salmon and flounder each year? Lett be measured in years. ○ S(t) - F(t) = 100e(-0.02)t ○ S(t) - F(t) = 100e(-0.02-0.01)t ○ S(t) - F(t) = e(-0.02)te(-0.01)t ○ S(t)- F(t) = = 100e(-0.01)t 100e(-0.01)t 100e(-0.02)t
A population of endangered salmon, S(t), starts out with 100 fish and decreases at a rate proportional to 0.02 times the number of fish present each year. A population of flounder, F(t), also starts out with a population of 100 fish and decreases at a rate proportional to 0.01 times the number of fish present each year. What is the equation which describes the difference between the number of salmon and flounder each year? Lett be measured in years. ○ S(t) - F(t) = 100e(-0.02)t ○ S(t) - F(t) = 100e(-0.02-0.01)t ○ S(t) - F(t) = e(-0.02)te(-0.01)t ○ S(t)- F(t) = = 100e(-0.01)t 100e(-0.01)t 100e(-0.02)t
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 6ECP: The resistance of a copper wire carrying an electrical current is directly proportional to its...
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![A population of endangered salmon, S(t), starts out with 100 fish and decreases at a rate proportional to 0.02 times the number of fish
present each year. A population of flounder, F(t), also starts out with a population of 100 fish and decreases at a rate proportional to
0.01 times the number of fish present each year.
What is the equation which describes the difference between the number of salmon and flounder each year?
Let t be measured in years.
○ S(t) F(t) = 100e(-0.02)t
–
100e(-0.01)t
○ S(t) F(t) = 100e(-0.02-0.01)t
-
○ S(t) - F(t) = e(-0.02)t e(-0.01)t
o S(t) F(t) = 100e(-0.01)t
−
100e(-0.02)t](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5fb4dfc3-db65-4bb6-9a5b-9427f46c7a3d%2Fd569c0cf-be09-4c52-869a-2eff835cc96b%2F7nppgh8_processed.png&w=3840&q=75)
Transcribed Image Text:A population of endangered salmon, S(t), starts out with 100 fish and decreases at a rate proportional to 0.02 times the number of fish
present each year. A population of flounder, F(t), also starts out with a population of 100 fish and decreases at a rate proportional to
0.01 times the number of fish present each year.
What is the equation which describes the difference between the number of salmon and flounder each year?
Let t be measured in years.
○ S(t) F(t) = 100e(-0.02)t
–
100e(-0.01)t
○ S(t) F(t) = 100e(-0.02-0.01)t
-
○ S(t) - F(t) = e(-0.02)t e(-0.01)t
o S(t) F(t) = 100e(-0.01)t
−
100e(-0.02)t
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