### Understanding the Distribution of Sample MeansA population has parameters μ = 41 and σ = 71.4. You intend to draw a random sample of size n = 174.#### Calculation Questions1. **What is the mean of the distribution of sample means?** \[ \mu_{\bar{x}} = \]2. **What is the standard deviation of the distribution of sample means?** *(Report answer accurate to 2 decimal places.)* \[ \sigma_{\bar{x}} = \]### Explanation:- **Mean of the Distribution of Sample Means (\( \mu_{\bar{x}} \))**: This is the same as the population mean (μ).- **Standard Deviation of the Distribution of Sample Means (\( \sigma_{\bar{x}} \))**: This is calculated using the population standard deviation (σ) divided by the square root of the sample size (n). The formula is: \[ \sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} \]For this specific problem, you would plug in the values as follows:\[ \sigma_{\bar{x}} = \frac{71.4}{\sqrt{174}} \]Be sure to perform the calculation accurately and round the result to two decimal places as requested.

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A population has parameters µ = 41 and o = 71.4. You intend to draw a random sample of s n = 174. What is the mean of the distribution of sample means? What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.)

A population has parameters µ = 41 and o = 71.4. You intend to draw a random sample of s n = 174. What is the mean of the distribution of sample means? What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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