A population has a mean of 1858.6 and standard deviation of 320.12. 10 A random sample of size n = 72 is selected from this population. The probability that the sample mean exceeds 1900 is. a с d 11 a b с 12 a b с 0.1253 0.1362 0.1481 0.1610 The fraction of the means from samples of size 72 that are below 1825 is, 0.1649 0.1754 0.1866 0.1985 The fraction of the means from samples of size 72 that are within ±60 from the population mean is, 0.9060 0.8883 0.8708 0.8538

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Questions 10-17 are related to the following information
A population has a mean of 1858.6 and standard deviation of 320.12.
10 A random sample of size n = 72 is selected from this population.
The probability that the sample mean exceeds 1900 is.
a
b
Po
с
d
11 The fraction of the means from samples of size 72 that are below 1825 is,
a
0.1649
0.1754
0.1866
0.1985
2002
b
с
d
12
200 23
૩
b
с
d
a
b
13 The margin of error for the middle interval that captures 95% of the sample means from samples of size 72
is,
с
d
14
a
b
с
d
a
2002
b
15 Suppose we double the sample size to n = 2 x 72 = 144.
Regarding the impact of changing the sample size on the margin of sampling error, doubling the sample size,
but keeping the error probability a at 5%, the MOE would,
29%
50%
52%
50%
с
d
a
b
0.1253
0.1362
0.1481
0.1610
f
с
d
The fraction of the means from samples of size 72 that are within ±60 from the population mean is,
0.9060
0.8883
0.8708
0.8538
16 The middle interval that captures 99% of all means from samples of size 72 is,
1739.6
a
73.94
71.10
68.36
65.73
с
d
The middle interval that captures 95% of the means from samples of size 72 is,
1768.02
1949.18
1773.94
1943.26
1779.48 1937.72
1784.66
1932.54
Decrease by
Decrease by
Decrease by
Increase by
17 Now keep the error probability at a = 0.05. We want to build an interval which captures 95% of the sample
means within +35 from the population mean. What is the minimum sample size that would yield such an
interval?
1977.6
1747.3
1969.9
1754.6 1962.6
1761.4 1955.8
354
322
293
266
Transcribed Image Text:Questions 10-17 are related to the following information A population has a mean of 1858.6 and standard deviation of 320.12. 10 A random sample of size n = 72 is selected from this population. The probability that the sample mean exceeds 1900 is. a b Po с d 11 The fraction of the means from samples of size 72 that are below 1825 is, a 0.1649 0.1754 0.1866 0.1985 2002 b с d 12 200 23 ૩ b с d a b 13 The margin of error for the middle interval that captures 95% of the sample means from samples of size 72 is, с d 14 a b с d a 2002 b 15 Suppose we double the sample size to n = 2 x 72 = 144. Regarding the impact of changing the sample size on the margin of sampling error, doubling the sample size, but keeping the error probability a at 5%, the MOE would, 29% 50% 52% 50% с d a b 0.1253 0.1362 0.1481 0.1610 f с d The fraction of the means from samples of size 72 that are within ±60 from the population mean is, 0.9060 0.8883 0.8708 0.8538 16 The middle interval that captures 99% of all means from samples of size 72 is, 1739.6 a 73.94 71.10 68.36 65.73 с d The middle interval that captures 95% of the means from samples of size 72 is, 1768.02 1949.18 1773.94 1943.26 1779.48 1937.72 1784.66 1932.54 Decrease by Decrease by Decrease by Increase by 17 Now keep the error probability at a = 0.05. We want to build an interval which captures 95% of the sample means within +35 from the population mean. What is the minimum sample size that would yield such an interval? 1977.6 1747.3 1969.9 1754.6 1962.6 1761.4 1955.8 354 322 293 266
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