A pop-up sprinkler sprays water in a semicircular area, as modeled in the figure below. What is the approximate area of lawn watered by the sprinkler?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

A pop-up sprinkler sprays water in a semicircular area, as modeled in the figure below. What is the approximate area of lawn watered by the sprinkler?

**Figure Explanation:**

The diagram shows a semicircle with a radius of 4 yards, centered on the sprinkler. The area covered by the sprinkler is represented by dashed lines emanating from the sprinkler, indicating the spread of water within the semicircular region.

**Multiple Choice Options:**

- 50.3 square yards
- 25.1 square yards
- 6.3 square yards
- 12.6 square yards

**Solution Explanation:**

To find the area of the semicircular region watered by the sprinkler, use the formula for the area of a circle and then divide by 2, since it's a semicircle:

\[ \text{Area of circle} = \pi r^2 \]

Here, \( r = 4 \) yards.

\[ \text{Area of circle} = \pi \times 4^2 = 16\pi \]

\[ \text{Area of semicircle} = \frac{16\pi}{2} = 8\pi \]

Approximating \( \pi \) as 3.14:

\[ \text{Area of semicircle} \approx 8 \times 3.14 = 25.12 \text{ square yards} \]

The approximate area of the lawn watered by the sprinkler is **25.1 square yards**.
Transcribed Image Text:**Problem Statement:** A pop-up sprinkler sprays water in a semicircular area, as modeled in the figure below. What is the approximate area of lawn watered by the sprinkler? **Figure Explanation:** The diagram shows a semicircle with a radius of 4 yards, centered on the sprinkler. The area covered by the sprinkler is represented by dashed lines emanating from the sprinkler, indicating the spread of water within the semicircular region. **Multiple Choice Options:** - 50.3 square yards - 25.1 square yards - 6.3 square yards - 12.6 square yards **Solution Explanation:** To find the area of the semicircular region watered by the sprinkler, use the formula for the area of a circle and then divide by 2, since it's a semicircle: \[ \text{Area of circle} = \pi r^2 \] Here, \( r = 4 \) yards. \[ \text{Area of circle} = \pi \times 4^2 = 16\pi \] \[ \text{Area of semicircle} = \frac{16\pi}{2} = 8\pi \] Approximating \( \pi \) as 3.14: \[ \text{Area of semicircle} \approx 8 \times 3.14 = 25.12 \text{ square yards} \] The approximate area of the lawn watered by the sprinkler is **25.1 square yards**.
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