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A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 67 metres per second. Its height in metres at t seconds is h(t)-(-5t+67)t. Find the time it hits the ground and the time it reaches its highest point. Include units in your answers. 1. Hits the ground when t 2. Reaches highest point when t 3. Maximum height=1805.6 m

A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 67 metres per second. Its height in metres at t seconds is h(t)-(-5t+67)t. Find the time it hits the ground and the time it reaches its highest point. Include units in your answers. 1. Hits the ground when t 2. Reaches highest point when t 3. Maximum height=1805.6 m

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Fast pls solve this question correctly in 5 min pls I will give u like for sure maximum height? Sub
A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 67 metres per second. Find the time it hits the ground and the time it reaches its highest point. Include units in your answers. 1. Hits the ground when t == 5 2. Reaches highest point when t = 3. Maximum height = 1805.6 m Its height in metres at t seconds is h(t)= (-5t+67)t. 67 10
Transcribed Image Text:A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 67 metres per second. Find the time it hits the ground and the time it reaches its highest point. Include units in your answers. 1. Hits the ground when t == 5 2. Reaches highest point when t = 3. Maximum height = 1805.6 m Its height in metres at t seconds is h(t)= (-5t+67)t. 67 10
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