A poll of 2,172 randomly selected adults showed that 92% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.93 vs p#0.93 Sample X N Sample p 95% CI Z-Value P-Value 1 1999 2,172 0.920350 (0.905386,0.935314) - 1.76 0.078

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A poll of 2,172 randomly selected adults showed that 92% of them own cell phones. The technology display below
results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to
the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e).
Test of p = 0.93 vs p+ 0.93
Sample X
Sample p
95% CI
Z-Value
P-Value
1
1999
2,172
0.920350
(0.905386,0.935314)
- 1.76
0.078
Transcribed Image Text:A poll of 2,172 randomly selected adults showed that 92% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.93 vs p+ 0.93 Sample X Sample p 95% CI Z-Value P-Value 1 1999 2,172 0.920350 (0.905386,0.935314) - 1.76 0.078
b. What is the test statistic?
The test statistic is - 1.31
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is .191.
(Round to three decimal places as needed.)
Transcribed Image Text:b. What is the test statistic? The test statistic is - 1.31 (Round to two decimal places as needed.) c. What is the P-value? The P-value is .191. (Round to three decimal places as needed.)
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