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A poll of 2,123 randomly selected adults showed that 88% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.93 vs p *0.93 Sample X 1 N 2,123 1861 Sample p 0.876590 95% CI (0.862599,0.890581) Z-Value -9.65 P-Value 0.000

A poll of 2,123 randomly selected adults showed that 88% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.93 vs p *0.93 Sample X 1 N 2,123 1861 Sample p 0.876590 95% CI (0.862599,0.890581) Z-Value -9.65 P-Value 0.000

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 14PPS
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Choose the correct answer below. A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, c. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, c. C. Reject the null hypothesis because the P-value is less than or equal to the significance level, c. O D. Reject the null hypothesis because the P-value is greater than the significance level, c. e. What is the final conclusion? O A. There is not sufficient evidence to support the claim that 93% of adults own a cell phone. B. There is sufficient evidence to support the claim that 93% of adults own a cell phone. OC. There is not sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone. D. There is sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone.
Transcribed Image Text:Choose the correct answer below. A. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, c. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, c. C. Reject the null hypothesis because the P-value is less than or equal to the significance level, c. O D. Reject the null hypothesis because the P-value is greater than the significance level, c. e. What is the final conclusion? O A. There is not sufficient evidence to support the claim that 93% of adults own a cell phone. B. There is sufficient evidence to support the claim that 93% of adults own a cell phone. OC. There is not sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone. D. There is sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone.
A poll of 2,123 randomly selected adults showed that 88% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p *0.93 Sample X N 1 2,123 1861 Right tailed test Left-tailed test a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Sample p 0.876590 b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? Identify the null hypothesis. O A. Ho: p<0.93 OB. Ho: p=0.93 95% CI (0.862599,0.890581) The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? O C. Ho: p*0.93 D. Ho: p > 0.93 Z-Value - 9.65 P-Value 0.000
Transcribed Image Text:A poll of 2,123 randomly selected adults showed that 88% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p *0.93 Sample X N 1 2,123 1861 Right tailed test Left-tailed test a. Is the test two-tailed, left-tailed, or right-tailed? Two-tailed test Sample p 0.876590 b. What is the test statistic? The test statistic is. (Round to two decimal places as needed.) c. What is the P-value? Identify the null hypothesis. O A. Ho: p<0.93 OB. Ho: p=0.93 95% CI (0.862599,0.890581) The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? O C. Ho: p*0.93 D. Ho: p > 0.93 Z-Value - 9.65 P-Value 0.000
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