A poll of 2,096 randomly selected adults showed that 91% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p *0.93 Sample XN 1 1903 2,096 Sample p 0.907920 95% CI (0.895542,0.920298) Z-Value -3.96 P.Value 0.000
A poll of 2,096 randomly selected adults showed that 91% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p=0.93 vs p *0.93 Sample XN 1 1903 2,096 Sample p 0.907920 95% CI (0.895542,0.920298) Z-Value -3.96 P.Value 0.000
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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![A poll of 2,096 randomly selected adults showed that 91% of them own cell phones. The technology display below results from a test of the
claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05
significance level to complete parts (a) through (e).
Test of p = 0.93 vs p *0.93
Sample X
N
1
2,096
1903
Sample p
0.907920
95% CI
(0.895542,0.920298)
Z-Value
-3.96
P-Value
0.000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F746c528c-1bb1-4b60-ba79-65bd8df817d1%2Ff655951f-e9a5-42c2-a4de-9cf75a4644b1%2Fd1b3rsv_processed.png&w=3840&q=75)
Transcribed Image Text:A poll of 2,096 randomly selected adults showed that 91% of them own cell phones. The technology display below results from a test of the
claim that 93% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05
significance level to complete parts (a) through (e).
Test of p = 0.93 vs p *0.93
Sample X
N
1
2,096
1903
Sample p
0.907920
95% CI
(0.895542,0.920298)
Z-Value
-3.96
P-Value
0.000
![b. What is the test statistic?
Z=
(Round to two decimal places as needed.)
c. What is the P-value?
P-value=
(Round to four decimal places as needed.)
d. What is the null hypothesis, and what do you conclude about it?
Identify the null hypothesis.
OA. Ho: p *0.08
OB. Ho: p=0.08
Oc. Ho:p> 0.08
OD. Ho: p<0.08
Decide whether to reject the null hypothesis. Choose the correct answer below.
OA. Reject the null hypothesis because the P-value is greater than the significance level, a.
OB. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
Oc. Fail to reject the null hypothesis because the P-value is greater than the significance level, a..
OD. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F746c528c-1bb1-4b60-ba79-65bd8df817d1%2Ff655951f-e9a5-42c2-a4de-9cf75a4644b1%2F9p1i1xd_processed.png&w=3840&q=75)
Transcribed Image Text:b. What is the test statistic?
Z=
(Round to two decimal places as needed.)
c. What is the P-value?
P-value=
(Round to four decimal places as needed.)
d. What is the null hypothesis, and what do you conclude about it?
Identify the null hypothesis.
OA. Ho: p *0.08
OB. Ho: p=0.08
Oc. Ho:p> 0.08
OD. Ho: p<0.08
Decide whether to reject the null hypothesis. Choose the correct answer below.
OA. Reject the null hypothesis because the P-value is greater than the significance level, a.
OB. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
Oc. Fail to reject the null hypothesis because the P-value is greater than the significance level, a..
OD. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.
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