A poll of 2,085 randomly selected adults showed that 95​% of them own cell phones. The technology display below results from a test of the claim that 91​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e).   Test of p=0.91 vs p≠0.91 Sample X N Sample p ​95% CI ​Z-Value ​P-Value 1 1971 2,085 0.945324 ​(0.932499​,0.958149​) 5.64   a. Is the test​ two-tailed, left-tailed, or​ right-tailed?   ​ b. What is the test​ statistic?   The test statistic is= (Round to two decimal places as​ needed.)   c. What is the​ P-value? The​ P-value is =​(Round to three decimal places as​ needed.)   d. What is the null hypothesis and what do you conclude about​ it? Identify the null hypothesis. A. H0: p=0.91 B. H0: p<0.91 C. H0: p>0.91 D. H0: p≠0.91   Choose the correct answer below. A. Reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α. B. Reject the null hypothesis because the​ P-value is greater than the significance​ level, α. C. Fail to reject the null hypothesis because the​ P-value is less than or equal to the significance​ level, α. D. Fail to reject the null hypothesis because the​ P-value is greater than the significance​ level, α.   e. What is the final​ conclusion? A. There is sufficient evidence to warrant rejection of the claim that 91​% of adults own a cell phone. B. There is not sufficient evidence to warrant rejection of the claim that 91​% of adults own a cell phone. C. There is not sufficient evidence to support the claim that 91​% of adults own a cell phone. D. There is sufficient evidence to support the claim that 91​% of adults own a cell phone.

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Author:Amos Gilat
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Chapter1: Starting With Matlab
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A poll of 2,085 randomly selected adults showed that 95​% of them own cell phones. The technology display below results from a test of the claim that 91​% of adults own cell phones. Use the normal distribution as an approximation to the binomial​ distribution, and assume a 0.01 significance level to complete parts​ (a) through​ (e).
 
Test of
p=0.91
vs
p≠0.91
Sample
X
N
Sample p
​95% CI
​Z-Value
​P-Value
1
1971
2,085
0.945324
​(0.932499​,0.958149​)
5.64
 
a. Is the test​ two-tailed, left-tailed, or​ right-tailed?
 
b. What is the test​ statistic?
 
The test statistic is= (Round to two decimal places as​ needed.)
 
c. What is the​ P-value?
The​ P-value is =​(Round to three decimal places as​ needed.)
 
d. What is the null hypothesis and what do you conclude about​ it?
Identify the null hypothesis.
A.
H0: p=0.91
B.
H0: p<0.91
C.
H0: p>0.91
D.
H0: p≠0.91
 
Choose the correct answer below.
A.
Reject
the null hypothesis because the​ P-value is
less than or equal to
the significance​ level, α.
B.
Reject
the null hypothesis because the​ P-value is
greater than
the significance​ level, α.
C.
Fail to reject
the null hypothesis because the​ P-value is
less than or equal to
the significance​ level, α.
D.
Fail to reject
the null hypothesis because the​ P-value is
greater than
the significance​ level, α.
 
e. What is the final​ conclusion?
A.
There
is
sufficient evidence to warrant rejection of the claim that
91​%
of adults own a cell phone.
B.
There
is not
sufficient evidence to warrant rejection of the claim that
91​%
of adults own a cell phone.
C.
There
is not
sufficient evidence to support the claim that
91​%
of adults own a cell phone.
D.
There
is
sufficient evidence to support the claim that
91​%
of adults own a cell phone.
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