A poll of 2,085 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 91% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p=0.91 vs p≠0.91 Sample X N Sample p 95% CI Z-Value P-Value 1 1971 2,085 0.945324 (0.932499,0.958149) 5.64 a. Is the test two-tailed, left-tailed, or right-tailed? b. What is the test statistic? The test statistic is= (Round to two decimal places as needed.) c. What is the P-value? The P-value is =(Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. A. H0: p=0.91 B. H0: p<0.91 C. H0: p>0.91 D. H0: p≠0.91 Choose the correct answer below. A. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. B. Reject the null hypothesis because the P-value is greater than the significance level, α. C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α. D. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. e. What is the final conclusion? A. There is sufficient evidence to warrant rejection of the claim that 91% of adults own a cell phone. B. There is not sufficient evidence to warrant rejection of the claim that 91% of adults own a cell phone. C. There is not sufficient evidence to support the claim that 91% of adults own a cell phone. D. There is sufficient evidence to support the claim that 91% of adults own a cell phone.
A poll of 2,085 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 91% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p=0.91 vs p≠0.91 Sample X N Sample p 95% CI Z-Value P-Value 1 1971 2,085 0.945324 (0.932499,0.958149) 5.64 a. Is the test two-tailed, left-tailed, or right-tailed? b. What is the test statistic? The test statistic is= (Round to two decimal places as needed.) c. What is the P-value? The P-value is =(Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. A. H0: p=0.91 B. H0: p<0.91 C. H0: p>0.91 D. H0: p≠0.91 Choose the correct answer below. A. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. B. Reject the null hypothesis because the P-value is greater than the significance level, α. C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, α. D. Fail to reject the null hypothesis because the P-value is greater than the significance level, α. e. What is the final conclusion? A. There is sufficient evidence to warrant rejection of the claim that 91% of adults own a cell phone. B. There is not sufficient evidence to warrant rejection of the claim that 91% of adults own a cell phone. C. There is not sufficient evidence to support the claim that 91% of adults own a cell phone. D. There is sufficient evidence to support the claim that 91% of adults own a cell phone.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A poll of 2,085 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 91% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e).
Test of
p=0.91
vs
p≠0.91
|
||||||
Sample
|
X
|
N
|
Sample p
|
95% CI
|
Z-Value
|
P-Value
|
---|---|---|---|---|---|---|
1
|
1971
|
2,085
|
0.945324
|
(0.932499,0.958149)
|
5.64
|
|
a. Is the test two-tailed, left-tailed, or right-tailed?
b. What is the test statistic?
The test statistic is= (Round to two decimal places as needed.)
c. What is the P-value?
The P-value is =(Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
A.
H0: p=0.91
B.
H0: p<0.91
C.
H0: p>0.91
D.
H0: p≠0.91
Choose the correct answer below.
A.
Reject
the null hypothesis because the P-value is
less than or equal to
the significance level, α.B.
Reject
the null hypothesis because the P-value is
greater than
the significance level, α.C.
Fail to reject
the null hypothesis because the P-value is
less than or equal to
the significance level, α.D.
Fail to reject
the null hypothesis because the P-value is
greater than
the significance level, α.e. What is the final conclusion?
A.
There
is
sufficient evidence to warrant rejection of the claim that
91%
of adults own a cell phone.B.
There
is not
sufficient evidence to warrant rejection of the claim that
91%
of adults own a cell phone.C.
There
is not
sufficient evidence to support the claim that
91%
of adults own a cell phone.D.
There
is
sufficient evidence to support the claim that
91%
of adults own a cell phone.Expert Solution
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