A poll of 2,004 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 92% distribution, and assume a 0.05 significance level to complete parts (a) through (e). adults own cell phones. Use the normal distribution as an approximation to the binomial Test of p = 0.92 vs p#0.92 Sample X Sample p 95% CI z-Value P-Value 1903 2.004 0.949601 (0.940023.0.959179) 4.88 0.000 a. Is the test two-tailed, left-tailed, or right-tailed? O Left-tailed test O Right tailed test O Two-tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. O A. Ho p<0.92 O B. Ho p#0.92 OC. Ho: p>0.92

MATLAB: An Introduction with Applications
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A poll of 2,004 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial
distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p = 0.92 vs p 0.92
Sample X
N
Sample p
95% CI
Z-Value
P-Value
1
1903
2.004
0.949601
(0.940023.0.959179)
4.88
0.000
a. Is the test two-tailed, left-tailed, or right-tailed?
Left-tailed test
Right tailed test
Two-tailed test
b. What is the test statistic?
The test statistic is
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
(Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
O A. Ho: p<0.92
О В. Но: р2 0.92
ОС. Но: р» 0.92
O D. Ho: p= 0.92
Transcribed Image Text:A poll of 2,004 randomly selected adults showed that 95% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). Test of p = 0.92 vs p 0.92 Sample X N Sample p 95% CI Z-Value P-Value 1 1903 2.004 0.949601 (0.940023.0.959179) 4.88 0.000 a. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed test Right tailed test Two-tailed test b. What is the test statistic? The test statistic is (Round to two decimal places as needed.) c. What is the P-value? The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. O A. Ho: p<0.92 О В. Но: р2 0.92 ОС. Но: р» 0.92 O D. Ho: p= 0.92
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