a poll of 125 randomly selected U.S. adults, 62 said they favored a new proposition. Based on this poll, compute a 90% confidence interval for the oportion of all U.S. adults in favor of the proposition (at the time of the poll). Then find the lower limit and upper limit of the 90% confidence interval. arry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: Upper limit:
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- In 2001, the polls found that 81% of American adults believed that there was a conspiracy in the death of President Kennedy. Assume a recent poll asked 1500 American adults if they believe there was a conspiracy in the assassination and it found that 1180 believe there was a conspiracy. Calculate a 91% confidence interval for the percentage of all Americans who believe in this conspiracy.In a survey of 2477 adults in a recent year, 1454 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals. The 90% confidence interval for the population proportion p is ,. (Round to three decimal places as needed.)Kit and Casey are each attempting to estimate the proportion of college students who can play at least one musical instrument. They each survey a different random sample of college students, and in each sample, the proportion who can play at least one musical instrument is 0.35. Kit and Casey each use their sample data to construct a confidence interval. Kit's interval is from 0.308 to 0.372 and Casey's interval is from 0.318 to 0.382. One of these intervals was computed correctly, but the other was not. Which interval must be incorrect? O Kit's interval must be incorrect. O It's impossible to answer this question without knowing the sample sizes. O It's impossible to answer this question without knowing the sample sizes or the level of confidence used for each interval. O Casey's interval must be incorrect. O It's impossible to answer this question without knowing the level of confidence used for each interval.
- You recently sent out a survey to determine if the percentage of adults who use social media has changed from 62%, which was the percentage of adults who used social media five years ago. Of the 2751 people who responded to survey, 1740 stated that they currently use social media.a) Use the data from this survey to construct a 98% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.b) Can you conclude that the percentage of adults who use social media has changed? Explain. Yes, because the proportion of adults who used social media five years ago is inside of the confidence interval. Yes, because the proportion of adults who used social media five years ago is not inside the confidence interval. No, because the proportion of adults who used social media five years ago is inside the confidence interval. No, because the proportion of adults who used social media…b. In the year 2000, a survey of 1171 U.S. adults were asked who they felt was the greatest President. Of those surveyed, 397 reported that Abraham Lincoln was the greatest President. Use this data to construct a 99% confidence interval for the population proportion of all U.S. adults who would say that Abraham Lincoln was the greatest president before the year 2000. Answer using decimals and round to four decimal placesprovide handwritten answer for part 4 only
- In a survey of 2275 adults, 709 say they believe in UFOS. Construct a 90% confidence interval for the population proportion of adults who believe in UFOS. A 90% confidence interval for the population proportion is ( ). (Round to three decimal places as needed.)Construct a 95% and 99% confidence interval of the age of adults with at most 3 vaccine shots. Compare the marginsof error for intervals. Base from your answers, make an inference in one or two sentences only.Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
- You recently sent out a survey to determine if the percentage of adults who use social media has changed from 56%, which was the percentage of adults who used social media five years ago. Of the 2335 people who responded to survey, 1725 stated that they currently use social media.a) Use the data from this survey to construct a 93% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.A college professor would like to estimate the proportion of students who pull an "all-nighter," meaning they study all night for an upcoming exam. She selects a random sample of 100 students from her large college and finds that the 99% confidence interval for the true proportion of students who pull an all-nighter is 0.48 to 0.62. Which of these statements is a correct interpretation of the confidence level? O Approximately 99% of all students have pulled an all-nighter. O There is a 99% probability that the true proportion of all students who pull an all-nighter is between 0.48 and 0.62. If many random samples of size 100 are selected from all students at this college, approximately 99% of the intervals would capture the true proportion who pull an all-nighter. C Approximately 99% of the sample proportions of students who pull an all-nighter, based on random samples of size 100 from the population of all students at this college, will fall between 0.48 and 0.62.The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. Suppose a sample of 1265 tenth graders is drawn. Of the students sampled, 1012 read above the eighth grade level. Using the data, construct the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.