A poll found that people from the north now have relatively warm feelings toward people from the south. A​ poll, conducted by telephone among a random sample of 1249​ adults, found that 737 of those sampled consider the two regions friends. The margin of error for the poll was plus or minus 2.7 percentage points​ (for a 0.95 confidence​ level). Use this information to obtain a 95​% confidence interval for the percentage of all northerners who consider the two regions friends. 1)The 95​% confidence interval is from negative ___% to ___​%.

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: Given that            sample size, n=20 Here, we have to construct a​ 95% confidence interval…

Q: A poll of 827 students at Alpha State College found that 61% of those polled preferred a quarter…

A: Given that Sample size n = 827 Sample proportion of students who prefer a quarter system = 0.61 The…

Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: The figure to the right shows the results of a survoy in which 1013 adults from Country A, 1001…

A: It was found that out of the 1013 adults from country A, 33% of the adults say national identity is…

Q: According to a Field Poll conducted February 8 – 17, 2005, 79% of California adults (actual results…

A: Solution

Q: a survey of 3088 adults aged 57 through 85​ years, it was found that 87.1​% of them used at least…

A: The formula for computing confidence interval is,  n is the sample size and P is the proportion.

Q: A telephone service representative believes that the proportion of customers completely satisfied…

A: See the handwritten solution

Q: Listed below are student evaluation ratings of courses, where a rating of 5 is for "excellent." The…

A: The 90% confidence interval for the population mean evaluation rating of courses, will signify that,…

Q: A survey was conducted to determine if adults in the U.S., France, and Germany believed humans…

A: The objective of this question is to construct 99% confidence intervals for the proportion of adults…

Q: A May 2000 Gallup poll found that 38% of a random sample of 1012 adults in the United States said…

A: (a)   Obtain the 96% confidence interval to estimate the true proportion of all U. S. adults who…

Q: n a survey of 500 students, 180 students said that they prefer classes on Mondays and Wednesdays…

A:

Q: . How many of the 3335 subjects used at least one prescription​ medication? b. Construct a​ 90%…

A: n = 3335 p = 0.804

Q: In a survey of 3110 adults aged 57 through 85 years, it was found that 87.9% of them used at least…

A:

Q: Kiyo is confused. He has constructed a 90% confidence interval for the average age of students at…

A: Answer: Given that:     Kiyo is confused. He has constructed a 90% confidence interval for the…

Q: he data given to the right includes data from 40 ​candies, and 7 of them are red. The company that…

A: given data, 7- red candies 40-total candies p^=xn=740=0.175CI=0.90α=1-0.90=0.10

Q: 829 adult were surveyed in one city, and 51% of them are opposed to the use of the photo-cop for…

A: Given data: n = 829 p = 0.51

Q: . The following information is from the article College Students' Attitudes Toward UFOs, (College…

A: given data x = 10n = 18090% confidence interval for p.

Q: In a survey of 3015 adults aged 57 through 85 years, it was found that 85.6% of them used at least…

A:

Q: An apartment hunter is shopping for either a one-bedroom or two-bedroom apartment in different…

A: Here the new variable is  X= difference  = (Two bed- One bed)  Then mean = ΣXi/n X̄ = (200 + 290 +…

Q: In a survey of 3115 adults aged 57 through 85​ years, it was found that 86.1​% of them used at…

A:

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: You are given the dataset representing the monthly salaries from a sample of thirty (30) Data…

A: Answer : sample x (x-x̄)^2 1 112276 337388320.9 2 108637 216947367.8 3 96818 8468875.824…

Q: In a survey of opinions regarding same-sex marriage, 14% of a sample of 1005 adults from Country A…

A: From the information, given thatn1=1005=0.14n 2=1987 = 0.17.The formula of the confidence interval…

Q: Listed below are student evaluation ratings of​ courses, where a rating of 5 is for​ "excellent."…

A: Given: student evaluation ratings of​ courses n=15α=0.01

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 443 green peas…

A: Find z-critical value:…

Q: In a survey of 3473 adults aged 57 through 85​ years, it was found that 84.6% of them used at least…

A:

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 443 green peas…

A: a) It is given that the number of yellow peas (x) is 156 and the green peas is 443. Therefore, the…

Q: The branch manager of an outlet store​ (Store 1) of a nationwide chain of pet supply stores wants to…

A: Comment: As per the our company guidelines we are supposed to answer only three subparts. Kindly…

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: Out of the given sample of size, n = 20 the number of presidents whose heights were more than their…

Q: Estimate 95% confidence interval for the proportion of household experiencing burglary in 2010."

A: 25.8 households per 1,000 were the victims of home burglary. These data are obtained from a survey…

Q: A 95% confidence interval for the average salary of all CEOs in the electronics industry was…

A: Given Sample size =40

Q: confidence interval estimate of the percentage of red candies. What do you conclude about the claim…

A: From provided information, company claims that 29% of candies are red. Out of 41 candies, 9 are red.…

Q: In a survey of 3393 adults aged 57 through 85​ years, it was found that 82.8​% of them used at least…

A: (a). Obtain the number of subjects who used at least one prescription medicine: It is given that…

Q: This questions has multiple subparts. For your convenience, the description of the problem is…

A: 90% confidence interval for the difference between the true proportion of men and the proportion of…

Q: In a survey of 3332 adults aged 57 through 85​ years, it was found that 80.7​% of them used at least…

A:

Q: An insurance company collects data on seat-belt use among drivers in a country. 90% confidence…

A: Givenn1=2000p1^=28%=0.28P2^=xn2=4821500=0.32α=1-0.90=0.10α2=0.05zc=zα2=z0.05=1.6449      (from z…

Q: a) What proportion of workers answered yes to the survey? b) What was the margin of error?

A: Here, the 95% confidence interval for the proportion of workers that answered 'yes' is (0.62, 0.73).…

Q: In a survey of 3116 adults aged 57 through 85​ years, it was found that 86.2​% of them used at least…

A: