A political poll of Americans was conducted to investigate their opinions on gun control.Each person was asked if they were in favor of gun control or not in favor of gun control,or I am not sure. The survey found that 25% of people contacted were not in favor ofgun control laws. These results were accurate to within 3 percentage points, with 95%confidence. Which of the following is NOT correct?a. The 95% confidence interval is approximately from 22% to 28%b. We are 95% confident that the true proportion of people not in favor of gun controlIis within 3 percentage points of 25%C. In approximately 95% polls on this issue, the confidence interval will include thesample proportion.d. If another poll of similar size were taken, the percentage of people IN FAVOR of guncontrol would likely range from 72% to 78%10,294APR1030atv AAaMacBook ProDIIDD20000D00F9F10F11F12F5F6F7F8F2F3F4

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Answered: A political poll of Americans was…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose you find that the 95% confidence interval for the cost of a wedding is ($29,000, $35,000). What is the correct interpretation of this interval? Group of answer choices For the next wedding you attend, the cost will be between $29,000 and $35,000. There is a 95% probability that the sample mean is between $29,000 and $35,000. There is a 95% probability that the population mean is between $29,000 and $35,000. You are 95% confident that the mean wedding cost is between $29,000 and $35,000. thanks
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
in a town in nj we take a random sample of 100 residents. It turns out that 25% of the adult residents have degrees higher than high school diploma. Find a 90% confidence interval.
The following summary of a statistical study gives a sample statistic and a margin of error. Find the confidence interval and answer any additional questions. A poll is conducted the day before a state election for senator. There are only two candidates running for this office. The poll results show that 55% of the voters favor the Republican candidate. with a margin of error of 3 percentage points. Should the Republican expect to win? Why or why not? % to %. The confidence interval is from (Simplify your answers. Use ascending order.)
The dean of students at a large college is interested in learning about their opinions regarding the percentage of first-year students who should be given parking privileges in the main lot. He sends out an email survey to all students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of students who believe first-year students should be given parking privileges in the main lot to be (0.71, 0.79). Which of the following may have an impact on the confidence interval, but is not accounted for by the margin of error? response bias O nonresponse bias O sampling variation O undercoverage bias
Which of the following confidence intervals would have a wider width for the same set of data? A 90% interval. A 99% interval. Group of answer choices The 90% interval. The 99% interval.
A college professor would like to estimate the proportion of students who pull an "all-nighter," meaning they study all night for an upcoming exam. She selects a random sample of 100 students from her large college and finds that the 99% confidence interval for the true proportion of students who pull an all-nighter is 0.48 to 0.62. Which of these statements is a correct interpretation of the confidence level? O Approximately 99% of all students have pulled an all-nighter. O There is a 99% probability that the true proportion of all students who pull an all-nighter is between 0.48 and 0.62. If many random samples of size 100 are selected from all students at this college, approximately 99% of the intervals would capture the true proportion who pull an all-nighter. C Approximately 99% of the sample proportions of students who pull an all-nighter, based on random samples of size 100 from the population of all students at this college, will fall between 0.48 and 0.62.
Statistics students surveyed 135 students at Tallahassee Community College. From their data we are 95% confident that between 44.7% and 61.9% of all TCC students are female. The students realize that this interval contains a large margin of error. What can they do to make a narrower interval? 1. Survey more students. 2. Use a 99% confidence level. 3. Survey more students and use a 99% confidence interval. 4. None of the other choices.
The following summary of a statistical study gives a sample statistic and a margin of error. Find the confidence interval and answer any additional questions. A poll is conducted the day before a state election for senator. There are only two candidates running for this office. The poll results show that 57% of the voters favor the Republican candidate, with a margin of error of 3 percentage points. Should the Republican expect to win? Why or why not? The confidence interval is from nothing% to nothing%. (Simplify your answers. Use ascending order.)
. In a random sample of 400 private high school students, 320 said they brought a smartphone to school that day, while in a random sample of 400 public high school students, 288 said they brought a smartphone to school that day. Which of the following represents a 98 percent confidence interval estimate for the difference (private high school minus public high school) between the proportions of all private high school and public high school students who bring a smartphone to school? (0.8)(0.2) (0.72)(0.28) (A) (0.8-0.72)±1.96, 400 400 (B) (0.8-0.72)±2.054, + (0.8)(0.2) (0.72)(0.28) 400 400 (C) (0.8-0.72)±2.326 + (0.8)(0.2) (0.72)(0.28) 400 400 1 (D) (0.8-0.72)±2.054, (0.76)(0.24) + 400 400 (E) (0.8-0.72)±2.326, (0.76)(0.24) + I 400 400
A poll was conducted to determine why Americans decide not to go to college. Of the 335 Americans who didn't go to college survey surveyed, 47% decided not to go to college because they couldn't afford it. Suppose we wanted the margin of error for the 90% confidence level to be about 1.5%. What sample size would you recommend for the survey? Round your answer appropriately.
If you want to be confident in your estimation of a confidence interval, you should use….

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