A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 0.5% margin of error at a 97.5% confidence level, what size of sample is needed? When finding the z-value, round it to four decimal places.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter10: Statistics
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**Sample Size Determination for Political Polling**

A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 0.5% margin of error at a 97.5% confidence level, what size of sample is needed? When finding the z-value, round it to four decimal places.

**Hint:** [Video Link]

**Note:** There is a rectangular box in the bottom left, presumably for users to input or calculate the required sample size.

**Explanation:**

To determine the sample size for a poll with specific margin of error and confidence level, you can use the sample size formula for proportions:

\[ n = \left( \frac{Z^2 \cdot p \cdot (1-p)}{E^2} \right) \]

Where:
- \( n \) is the sample size.
- \( Z \) is the z-value corresponding to the confidence level.
- \( p \) is the estimated proportion of an attribute that is present in the population (use 0.5 if unknown).
- \( E \) is the margin of error.

For a 97.5% confidence level, find the corresponding z-value (round to four decimal places), and use the desired margin of error (0.5%) to calculate the sample size.
Transcribed Image Text:**Sample Size Determination for Political Polling** A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 0.5% margin of error at a 97.5% confidence level, what size of sample is needed? When finding the z-value, round it to four decimal places. **Hint:** [Video Link] **Note:** There is a rectangular box in the bottom left, presumably for users to input or calculate the required sample size. **Explanation:** To determine the sample size for a poll with specific margin of error and confidence level, you can use the sample size formula for proportions: \[ n = \left( \frac{Z^2 \cdot p \cdot (1-p)}{E^2} \right) \] Where: - \( n \) is the sample size. - \( Z \) is the z-value corresponding to the confidence level. - \( p \) is the estimated proportion of an attribute that is present in the population (use 0.5 if unknown). - \( E \) is the margin of error. For a 97.5% confidence level, find the corresponding z-value (round to four decimal places), and use the desired margin of error (0.5%) to calculate the sample size.
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