A polisher is started so that the fleece along the circumference undergoes a constant tangential acceleration of 5 m/s 2. Five seconds after a polisher is started from rest, small tufts of fleece from along the circumference of the 250-mm-diameter polishing pad are observed to fly free of the pad. At this instant, determine (a) the speed v of a tuft as it leaves the pad, (b) the magnitude of the force required to free a tuft if the average mass of a tuft is 1.5 mg. OFt -> 0.009, v -> 25., Ftan -> 9.*10^-6, Fnorm -> 0.009 Ft-> 0.009375, v -> 25., Ftan -> 7.5*10^-6, Fnorm > 0.009375 Ft -> 0.0075, v -> 25., Ftan -> 7.5 10^-6, Fnorm -> 0.0075 Ft-> 0.0192, v -> 40., Ftan -> 7.5*10^-6, Fnorm -> 0.0192
A polisher is started so that the fleece along the circumference undergoes a constant tangential acceleration of 5 m/s 2. Five seconds after a polisher is started from rest, small tufts of fleece from along the circumference of the 250-mm-diameter polishing pad are observed to fly free of the pad. At this instant, determine (a) the speed v of a tuft as it leaves the pad, (b) the magnitude of the force required to free a tuft if the average mass of a tuft is 1.5 mg. OFt -> 0.009, v -> 25., Ftan -> 9.*10^-6, Fnorm -> 0.009 Ft-> 0.009375, v -> 25., Ftan -> 7.5*10^-6, Fnorm > 0.009375 Ft -> 0.0075, v -> 25., Ftan -> 7.5 10^-6, Fnorm -> 0.0075 Ft-> 0.0192, v -> 40., Ftan -> 7.5*10^-6, Fnorm -> 0.0192
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A polisher is started so that the fleece along the circumference undergoes a constant
tangential acceleration of 5 m/s 2. Five seconds after a polisher is started from rest,
small tufts of fleece from along the circumference of the 250-mm-diameter polishing
pad are observed to fly free of the pad. At this
instant, determine (a) the speed v of a tuft as it leaves the pad, (b) the magnitude of
the force required to free a tuft if the average mass of a tuft is 1.5 mg.
O Ft -> 0.009, v -> 25., Ftan -> 9.*10^-6, Fnorm -> 0.009
Ft-> 0.009375, v -> 25., Ftan -> 7.5*10^-6, Fnorm > 0.009375
Ft-> 0.0075, v -> 25., Ftan -> 7.5 10^-6, Fnorm -> 0.0075
Ft-> 0.0192, v -> 40., Ftan -> 7.5*10^-6, Fnorm -> 0.0192
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