A point P(3,0,5) lies on a plane that can be defined by the scalar equation Ax+By+Cz+ D = 0. A normal vector, n, to this plane is (2,-3,1). Find the scalar equation.

Q: Write the scalar equation of the line given the normal vector point Po(-2,-4). n = and a

A: Scalar equation of a line is given by , Ax+By+C =0, where (A,B) are the cordinates of normal vector…

Q: Find a scalar equation of the plane containing the line and the point (-5, -1,5). x = 6 +8t, y=-1-3t…

A:

Q: Construct a vector that is perpendicular to the plane containing (−2, 4, 1),(3, 3, -1) and (1, 0,…

A: Construct a vector that is perpendicular to the plane containing (-2,4,1),(3,3,-1) and (1,0,2)

Q: 7. Find the scalar equation of any plane which contains the line = (1,2,1)+ t(3,6,-1)

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Q: Find an equation of the plane that passes through the point Po(0, -2,3) with a normal vector n =…

A: To find the equation of a plane that passes through the point with a normal vector , you can use…