A point moves on the parabola 10y = 5x² + 3 in such a way that when x = 6, the abscissa is increasing at the rate of 2 ft per second. At what rate is the ordinary increasing at that point?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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A point moves on the parabola 10y = 5x2 + 3 in such a way that when x =
abscissa is increasing at the rate of 2 ft per second. At what rate is the ordinary
6, the
increasing at that point?
Transcribed Image Text:A point moves on the parabola 10y = 5x2 + 3 in such a way that when x = abscissa is increasing at the rate of 2 ft per second. At what rate is the ordinary 6, the increasing at that point?
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Step 1: Given.

Given: A point moves on the parabola 10y=5x2+3, when x=6 the abscissa is increasing at the rate of 2 ft per second.

To find: At what rate the ordinary is increasing.

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