A point A(-5,-3) is translated by the vector v = <8, 0>, and then reflected about the line y=0. the coordinates of its image A are

Suppose the positive x-, y-, and z-axes point east, north, and upward, respectively. Describe the location of the points (-1, -1, 0), (1, 0, 1), and (-1, -1, -1) relative to the origin.

A line contains the points P=(−6,−2,−3)P=(-6,-2,-3) and Q=(−4,−3,−6)Q=(-4,-3,-6). A vector equation of this line is →x=−−→OP+t−−→PQx→=OP→+tPQ→, where OO is the origin.If t=2t=2, what point does this give us from the equation?