A plumber pushes straight down on the end of a long wrench as shown. What is the magnitude of the torque he applies about the pipe at lower right? Derive and tick below A. (0.80 m)(900 N)sin 19° B. (0.80 m)(900 N)cos 19° 0.80 m C. (0.80 m)(9000 N)sin 19° F= 900 N 19 D. (0.80 m)(90 N)cos 19° E. (0.80 m)(90 N)sin 19°

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Chapter1: Units, Trigonometry. And Vectors
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A plumber pushes straight down on the end of a long wrench as shown. What is the
magnitude of the torque he applies about the pipe at lower right? Derive and tick below
A. (0.80 m)(900 N)sin 19°
B. (0.80 m)(900 N)cos 19°
0.80 m
C. (0.80 m)(9000 N)sin 19°
F = 900 N
19
D. (0.80 m)(90 N)cos 19°
E. (0.80 m)(90 N)sin 19°
n ng
Transcribed Image Text:A plumber pushes straight down on the end of a long wrench as shown. What is the magnitude of the torque he applies about the pipe at lower right? Derive and tick below A. (0.80 m)(900 N)sin 19° B. (0.80 m)(900 N)cos 19° 0.80 m C. (0.80 m)(9000 N)sin 19° F = 900 N 19 D. (0.80 m)(90 N)cos 19° E. (0.80 m)(90 N)sin 19° n ng
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