A plot of enzyme activity with and without an inhibitor present gave the following. Use two significant figures in all numerical answers. 1/v (v in mM/min) 1.6 1.5 1.4 1.3 1.2 1.1 1 0 0.2 y = 0.11x +1.42 y = 0.11x +1.26 0.4 0.6 1/[S] ([S] in mM) Without the inhibitor, what is the Km? Without the inhibitor, what is the Vmax? What type of inhibitor is present? In the presence of the inhibitor, what is the Km? In the presence of the inhibitor, what is the Vmax? 0.8 mM mM/min mM mM/min
A plot of enzyme activity with and without an inhibitor present gave the following. Use two significant figures in all numerical answers. 1/v (v in mM/min) 1.6 1.5 1.4 1.3 1.2 1.1 1 0 0.2 y = 0.11x +1.42 y = 0.11x +1.26 0.4 0.6 1/[S] ([S] in mM) Without the inhibitor, what is the Km? Without the inhibitor, what is the Vmax? What type of inhibitor is present? In the presence of the inhibitor, what is the Km? In the presence of the inhibitor, what is the Vmax? 0.8 mM mM/min mM mM/min
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question
Q27
![A plot of enzyme activity with and without an inhibitor present gave the following. Use two
significant figures in all numerical answers.
1/v (v in mM/min)
1.6
1.5
1.4
1.3
1.2
1.1
1
0
0.2
y = 0.11x +1.42
y = 0.11x +1.26
0.4
0.6
1/[S] ([S] in mM)
Without the inhibitor, what is the Km?
Without the inhibitor, what is the Vmax?
What type of inhibitor is present?
In the presence of the inhibitor, what is the Km?
In the presence of the inhibitor, what is the Vmax?
0.8
mM
mM/min
mM
mM/min](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffdac5784-6171-4c2d-813f-cbb526f56bfb%2F0b0e79a8-1af9-4ac7-ae21-17fcf4fe4b82%2F96cfrgi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A plot of enzyme activity with and without an inhibitor present gave the following. Use two
significant figures in all numerical answers.
1/v (v in mM/min)
1.6
1.5
1.4
1.3
1.2
1.1
1
0
0.2
y = 0.11x +1.42
y = 0.11x +1.26
0.4
0.6
1/[S] ([S] in mM)
Without the inhibitor, what is the Km?
Without the inhibitor, what is the Vmax?
What type of inhibitor is present?
In the presence of the inhibitor, what is the Km?
In the presence of the inhibitor, what is the Vmax?
0.8
mM
mM/min
mM
mM/min
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