A planet of mass 5 x 1024 kg is at location (S x 1011, -5 x 1011, o) m. A star of mass 5 x 1030 kg is at location (-6 x 1011, 5 x 1011, 0) m. It will be useful to draw a diagram of the situation, including the relevant vectors. (a) What is the relative position vector r pointing from the planet to the star? r= <-1.1.1012 1. 1012,0 > m (b) What is the distance between the planet and the star? Irl = |14.86e11 (c) What is the unit vector in the direction of r? 7 = <-.74,.67,0 > (d) What is the magnitude of the force exerted on the planet by the star? |Fon planetl = 7.56e42 X N (e) What is the magnitude of the force exerted on the star by the planet? Fon starl = (f) What is the force (vector) exerted on the planet by the star? (Note the change in units.) Fon planet = x 1020 N (g) What is the force (vector) exerted on the star by the planet? (Note the change in units.) Fon star= x 1020 N
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
Please answer d,e,f,g
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