A piston-cylinder device contains 2.2 kg of nitrogen initial nitrogen is now compressed slowly in a polytropic process constant until the volume is reduced by one-half Determin
A piston-cylinder device contains 2.2 kg of nitrogen initial nitrogen is now compressed slowly in a polytropic process constant until the volume is reduced by one-half Determin
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Problem Statement
A piston–cylinder device contains 2.2 kg of nitrogen initially at 100 kPa and 25°C. The nitrogen is now compressed slowly in a polytropic process during which \( PV^{1.3} = \) constant until the volume is reduced by one-half. Determine the work done and the heat transfer for this process, in kJ. Use \( R = 0.2968 \, \text{kJ/kg.K} \) and \( C_v = 0.744 \, \text{kJ/kg.K} \).
### Explanation and Calculations
1. **Initial Conditions:**
- Mass (\( m \)): 2.2 kg
- Initial Pressure (\( P_1 \)): 100 kPa
- Initial Temperature (\( T_1 \)): 25°C (or 298 K)
2. **Process Description:**
- Polytropic process with \( PV^{1.3} = \) constant.
- Volume is reduced by half.
3. **Process Equations:**
- Use the ideal gas law for initial state:
\[ P_1V_1 = mRT_1 \]
- For polytropic processes:
\[ W = \frac{P_2V_2 - P_1V_1}{1-n} \]
- Use the given \( n = 1.3 \).
4. **Finding Final State and Calculations:**
- Use the relationship \( V_2 = \frac{V_1}{2} \).
- Substitute \( n \) into the polytropic formula for further calculations.
5. **Heat Transfer:**
- Employ the first law of thermodynamics:
\[ Q = \Delta U + W \]
- Calculate change in internal energy using:
\[ \Delta U = mC_v(T_2 - T_1) \]
Conduct these calculations step-by-step to find the work done and heat transfer in kJ for the given compression process.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa437b1f1-94c0-462c-9640-81b3f97959f1%2F02bb6245-fe57-4d89-a489-b9a8fe1838c4%2F0ayyz5_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement
A piston–cylinder device contains 2.2 kg of nitrogen initially at 100 kPa and 25°C. The nitrogen is now compressed slowly in a polytropic process during which \( PV^{1.3} = \) constant until the volume is reduced by one-half. Determine the work done and the heat transfer for this process, in kJ. Use \( R = 0.2968 \, \text{kJ/kg.K} \) and \( C_v = 0.744 \, \text{kJ/kg.K} \).
### Explanation and Calculations
1. **Initial Conditions:**
- Mass (\( m \)): 2.2 kg
- Initial Pressure (\( P_1 \)): 100 kPa
- Initial Temperature (\( T_1 \)): 25°C (or 298 K)
2. **Process Description:**
- Polytropic process with \( PV^{1.3} = \) constant.
- Volume is reduced by half.
3. **Process Equations:**
- Use the ideal gas law for initial state:
\[ P_1V_1 = mRT_1 \]
- For polytropic processes:
\[ W = \frac{P_2V_2 - P_1V_1}{1-n} \]
- Use the given \( n = 1.3 \).
4. **Finding Final State and Calculations:**
- Use the relationship \( V_2 = \frac{V_1}{2} \).
- Substitute \( n \) into the polytropic formula for further calculations.
5. **Heat Transfer:**
- Employ the first law of thermodynamics:
\[ Q = \Delta U + W \]
- Calculate change in internal energy using:
\[ \Delta U = mC_v(T_2 - T_1) \]
Conduct these calculations step-by-step to find the work done and heat transfer in kJ for the given compression process.
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