A pipe inclined at 45° to the horizontal (Fig. 2) converges over a length l of 2 m from a diameter d1 of 200 mm to a diameter d2 of 100 mm at the upper end. Oil of relative density 0.9 flows through the pipe at a mean velocity ?̅1 at the lower end of 2 m/s. Find the pressure difference across the 2 m length ignoring any loss of energy, and the difference in level that would be shown on a mercury manometer connected across this length. The relative density of mercury is 13.6 and the leads to the manometer are filled with the oil.
A pipe inclined at 45° to the horizontal (Fig. 2) converges over a length l of 2 m from a diameter d1 of 200 mm to a diameter d2 of 100 mm at the upper end. Oil of relative density 0.9 flows through the pipe at a mean velocity ?̅1 at the lower end of 2 m/s. Find the pressure difference across the 2 m length ignoring any loss of energy, and the difference in level that would be shown on a mercury manometer connected across this length. The relative density of mercury is 13.6 and the leads to the manometer are filled with the oil.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
A pipe inclined at 45° to the horizontal (Fig. 2) converges over a length l of 2 m from a diameter
d1 of 200 mm to a diameter d2 of 100 mm at the upper end. Oil of relative density 0.9 flows
through the pipe at a mean velocity ?̅1 at the lower end of 2 m/s. Find the pressure difference
across the 2 m length ignoring any loss of energy, and the difference in level that would be
shown on a mercury manometer connected across this length. The relative density of mercury is 13.6 and the leads to the manometer are
filled with the oil.
Transcribed Image Text:₁ = 2 ms¹
d₁ = 200 mm
S
/= 2m
-145-
7₂
Mercury of mass density
Pman-PHg = 13.6PH₂0
=100mm
Oil of mass density
Poil = 0.9 P1₂0
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