A piece of metal with a mass of 21.08 grams is initially heated to 98.0°C. The metal issubmerged into 47.00 grams of water with an initial temperature of 22.0°C. Whenthe metal/water reach thermal equilibrium the final temperature is 26.0°C.Calculate the specific heat capacity of the metal.The specific heat capacity of the water is 4.184 J/g/°CDo not type units with your answer.Your Answer:

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Answered: A piece of metal with a mass of 21.08…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A silver block, initially at 55.0 °C, is submerged into 100.0 grams of water at 25.8 °C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 28.0°C. What is the mass of the silver block? The specific heat capacity of silver is 0.235 J/g°C The specific heat capacity of water is 4.184 J/g°C To minimize rounding errors report your final answer with one decimal place. I'm not going to worry about significant figures on this question. Do not type units with your answer. Your Answer:
A piece of titanium metal with a mass of 21.6 g is heated in boiling water to 99.5 °C and then dropped into a coffee-cup calorimeter containing 75.0 g of water at 21.8 °C. When thermal equilibrium is reached, the final temperature is 24.5 °C. Calculate the specific heat capacity of titanium. (The specific heat capacity of liquid water is 4.184 J/g. K.) Specific heat capacity= J/g. K
A 46.9-g iron rod, initially at 18.6 oC is submerged into 50.4 g of water at an unknown initial temperature. The final temperature of the mixture upon reaching thermal equilibrium is 69.6 oC. What is the initial temperature of the water (in oC)? The specific heat capacity of iron is 0.449 J/g.oC The specific heat capacity of water is 4.184 J/g.oC
A calorimeter contained 67.0 g of water at 15.93°C. A 110.-g sample of iron at 66.42°C was placed in it, giving a final temperature of 19.42°C for the system. Calculate the heat capacity of the calorimeter. Specific heats are 4.184 J/g-°C for H2O and 0.444 J/g-°C for Fe. Heat capacity of the calorimeter =
A 149.2-g sample of a metal at 74.4°C is added to 149.2 g H20 at 15.5°C. The temperature of the water rises to 18.6°C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water. The specific heat capacity of water is 4.18 J/°C g. Specific heat capacity = | J/°C•&
A hot 122.8 g lump of an unknown substance initially at 154.8 °C is placed in 35.0 mL of water initially at 25.0 °C and the system is allowed to reach thermal equilibrium. The final temperature of the system is 56.9 °C. Using this information and the specific heat values for several metals in the table, identify the unknown substance. Assume no heat is lost to the surroundings. graphite zinc aluminum titanium tungsten rhodium Substance Specific heat (J/(g-°C)) aluminum 0.897 graphite 0.709 rhodium 0.243 titanium 0.523 0.132 0.388 4.184 tungsten zinc water
A metal object with mass of 20.9 g is heated to 97.0 °C and then transferred to an insulated container containing 83.1 g of water at 20.5 °C. The water temperature rises and the temperature of the metal object falls until they both reach the same final temperature of 23.9 °C. What is the specific heat of this metal object? Assume that all the heat lost by the metal object is absorbed by the water. specific heat: cal TOOLS x10 DII DD F4 F5
A silver block, initially at 51.0 °C, is submerged into 100.0 grams of water at 25.3 °C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 28.0°C. What is the mass of the silver block? The specific heat capacity of silver is 0.235 J/g°C The specific heat capacity of water is 4.184 J/g°C Do not type units with your answer. Type your answer to four significant figures. If this question is on an exam on your scrap paper report your answer to the proper number of significant figures but still type four significant figures online.
A 151.6-g sample of a metal at 74.7°C is added to 151.6 g at 15.9°C. The temperature of the water rises to 18.2°C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water. The specific heat capacity of water is 4.18 J/°C ⋅ g. Specific heat capacity = ________J/°C ⋅ g
When an 28.6 g sample of an unknown metal at 142.2 °C is placed into 99.4 g of water at 21.7 °C the final temperature is 31.2 °C. What is the specific heat capacity of the metal in J/g°C
Can you explain where did I go wrong, I keep getting the same answer.
A metal object with mass of 21.4 g is heated to 97.0 °C and then transferred to an insulated container containing 81.7 g of water at 20.5°C. The water temperature rises and the temperature of the metal object falls until they both reach the same final temperature of 23.1 °C. What is the specific heat of this metal object? Assume that all the heat lost by the metal object is absorbed by the water. cal specific heat:

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