A pianist plans to play 5 pieces at a recital from her repertoire of 20 pieces, and is carefully considering which song to play first, second, etc. to create a good flow. How many different recital programs are possible?
A pianist plans to play 5 pieces at a recital from her repertoire of 20 pieces, and is carefully considering which song to play first, second, etc. to create a good flow. How many different recital programs are possible?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
A pianist plans to play 5 pieces at a recital from her repertoire of 20 pieces, and is carefully considering which song to play first, second, etc. to create a good flow. How many different recital programs are possible?
![**Problem Statement:**
A pianist plans to play 5 pieces at a recital from her repertoire of 20 pieces, and is carefully considering which song to play first, second, etc. to create a good flow. How many different recital programs are possible?
**Solution Explanation:**
To solve this problem, consider that the order in which the pieces are played matters. This situation involves permutations since you are arranging 5 pieces out of 20.
**Permutations Formula:**
The number of permutations of choosing \( r \) items from \( n \) items is given by the formula:
\[
P(n, r) = \frac{n!}{(n-r)!}
\]
**Application to the Problem:**
- \( n = 20 \) (total pieces)
- \( r = 5 \) (pieces to be played)
Using the formula:
\[
P(20, 5) = \frac{20!}{(20-5)!} = \frac{20!}{15!}
\]
Calculating this gives:
\[
= 20 \times 19 \times 18 \times 17 \times 16
\]
\[
= 1,860,480
\]
Therefore, there are **1,860,480** different possible recital programs.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5fbd16d4-9c69-410f-bf63-af68718d9228%2F2a9be4e5-c07c-452a-926f-9a06d0c4f008%2F8exqyk7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A pianist plans to play 5 pieces at a recital from her repertoire of 20 pieces, and is carefully considering which song to play first, second, etc. to create a good flow. How many different recital programs are possible?
**Solution Explanation:**
To solve this problem, consider that the order in which the pieces are played matters. This situation involves permutations since you are arranging 5 pieces out of 20.
**Permutations Formula:**
The number of permutations of choosing \( r \) items from \( n \) items is given by the formula:
\[
P(n, r) = \frac{n!}{(n-r)!}
\]
**Application to the Problem:**
- \( n = 20 \) (total pieces)
- \( r = 5 \) (pieces to be played)
Using the formula:
\[
P(20, 5) = \frac{20!}{(20-5)!} = \frac{20!}{15!}
\]
Calculating this gives:
\[
= 20 \times 19 \times 18 \times 17 \times 16
\]
\[
= 1,860,480
\]
Therefore, there are **1,860,480** different possible recital programs.
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