A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon? ОО OO 0.25 nm 150 nm 50 nm 2.0 nm not enough information given
A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon? ОО OO 0.25 nm 150 nm 50 nm 2.0 nm not enough information given
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Photon Wavelength Question
A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon?
- [ ] 0.25 nm
- [ ] 150 nm
- [ ] 50 nm
- [ ] 2.0 nm
- [ ] Not enough information given
**Explanation:**
To solve this problem, one should understand that the de Broglie wavelength can be computed using the relationship between a particle's momentum and its wavelength. For a photon, the wavelength (\(\lambda\)) is related to momentum (\(p\)) via the equation \( \lambda = \frac{h}{p} \), where \(h\) is Planck's constant.
For electrons, the de Broglie wavelength also follows \( \lambda = \frac{h}{p} \). Given that the photon and the electron have the same momentum in this problem, we can directly compare their wavelengths.
No diagrams or graphs are included with this question.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45c459d4-c7f0-416a-8b1d-00b29b90700e%2F1c5d03a6-1d63-4ef1-ac29-d8470824e7d1%2Fwygt8ra_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Photon Wavelength Question
A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon?
- [ ] 0.25 nm
- [ ] 150 nm
- [ ] 50 nm
- [ ] 2.0 nm
- [ ] Not enough information given
**Explanation:**
To solve this problem, one should understand that the de Broglie wavelength can be computed using the relationship between a particle's momentum and its wavelength. For a photon, the wavelength (\(\lambda\)) is related to momentum (\(p\)) via the equation \( \lambda = \frac{h}{p} \), where \(h\) is Planck's constant.
For electrons, the de Broglie wavelength also follows \( \lambda = \frac{h}{p} \). Given that the photon and the electron have the same momentum in this problem, we can directly compare their wavelengths.
No diagrams or graphs are included with this question.
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