**Question 21 of 26**A photon has a frequency of \(8.97 \times 10^8\) Hz. What is the energy of this photon in Joules? (Planck's constant, \(h = 6.626 \times 10^{-34}\) J·s)---**Explanation:**To calculate the energy of a photon, we use the formula:\[ E = h \times f \]where \(E\) is the energy, \(h\) is Planck's constant (\(6.626 \times 10^{-34}\) J·s), and \(f\) is the frequency of the photon.For this problem:\[ E = 6.626 \times 10^{-34} \, \text{J·s} \times 8.97 \times 10^8 \, \text{Hz} \]\[ E = 5.94 \times 10^{-25} \, \text{J} \]---**Interactive Features:**- A numeric keypad is provided for user input.- Options for entering positive or negative exponents.- A clear button (C) for resetting inputs.- A multiplication by 10 option for quick calculations.**Additional Resources:** Tap the bottom bar for more information on photon energy and Planck's constant.

Given, Frequency of a photon (v) = 8.97 × 108 Hz = 8.97 × 108 s-1 Energy of a photon (E) = ? Note:…

Answered: A photon has a frequency of 8.97 x 108…

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Chemistry

A photon has a frequency of 8.97 x 108 Hz. What is the energy of this photon in Joules? (h = 6.626 x 10-34 J. s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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