A photograph is taken of a missile moving at 1800 ms'. The bottom edge of the image is horizontal. What is the horizontal component of its velocity at the instant shown?
Q: 15 m/s 3.9 m
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A: Answer is attached below ??Explanation:
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Q: image
A: A = 35 degree u = 11 m/s T =2.9 s
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A: SOLUTION ;FROM GIVEN DATA
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Q: Q1. An archer aims at the bullseye of a target 50.0 m away. The arrow is at the same height as the…
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Q: Consider a projectile being launched with an initial speed of 43 m/s at a variety of initial angles.…
A: Given u =43 m/s
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- This problem will involve deriving a formula or two for a projectile launched from one height and angle and landing at a different height on Earth. Begin with a projectile launched at angle 0 above horizontal from a height y₁ with initial velocity Vo. The projectile lands at a point with height y₂. These are the given quantities: vo, 0, y₁, y2 and g. Construct formulae for each of the following, as. a function of given quantities the horizontal distance traveled. the maximum height reached. the time taken. the angle of impact. (find the final velocity components first).3. Consider a ball undergoing a 2D projectile motion, whose position (unit: m) as a function of time (unit: s) is 3(t) = tî + (V3t – 5t²)ĵ, where t stands for time. (a) Find the initial launch angle of the projection. (b) Find the speed of the ball when it lands on the ground.San Francisco Giants mascot Lou Seal is trying to shoot t-shirts into the crowd at Oracle Park. Lou wants to deliver a t-shirt into the hands of a fan standing 40 m away horizontally but 16 m above the launch point. If he angles the t-shirt cannon 45 degrees above the horizontal, what speed does the cannon need to launch at to get the t-shirt to the fan? (You can ignore air resistance in this problem).
- Dr. L. and his cat Kepler are coming home from fishing. They ended their trip on the southbank of a 1200 m wide river, directly across from where Caroline is waiting to pick them upon the north bank. They are in identical boats that travel at 4 m/s (VB) on still water. Theriver is normally ‘lazy’ and flows with negligible velocity. On a calm day, if they pointed theboats north, they would cross the river in exactly 300s. However, today, the river is flowingdue east with a constant velocity (VW) of 1 m/s relative to the ground. Kepler, because shedoesn’t know better (she is a cat after all), has not taken this into account. Without payingattention, Kepler keeps the boat pointed due north for the entire trip. A) Relative to the ground, what is Kepler’s velocity? Derive an algebraic solution(in terms of VB and VW only) and then give a numerical answer (three significant figures isfine) expressed in degrees relative to due north (e.g. ‘42.3° west of north’).Find the ranges shown for the projectiles in the figure for an initial speed of 50 m/s at the given initial angles. Part A: What is the range, in meters, for the projectile with the angle of 15°? Part B: What is the range, in meters, for the projectile with the angle of 45°? Part C: What is the range, in meters, for the projectile with the angle of 75°?Question: Diego is getting hungry and acting like a typical saber-toothed tiger. He visualizes Sid as a hunk of meat and begins to chase him frantically around the ground. First, Sid darts 50.0 meters at 35.0° NoW and then turns abruptly and races 40.0 m S. If Manny ran from where they were originally standing to where Sid ended up, how far and in what direction would Manny have to run to break up the fight? Use the triangle method to solve this. Should you use the component method, I will award zero points. I know the answer I just don’t know how to get it. Answer: 42.5 m @ 15.5° SoW Thanks!!