A person with compromised pinch strength in his fingers can exert a force of only 6.0 N to either side of a pinch-held object, such as the book shown in (Figure 1). Figure < 1 of 1 > Part A What is the heaviest the book he can hold vertically before it slips out of his fingers? The coefficient of static friction between his fingers and the book cover is 0.76. Express your answer in newtons. Fa = Submit IVE ΑΣΦ Provide Feedback Request Answer ? N Next >

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Topic Video
Question
### Educational Exercise on Static Friction

#### Problem Statement:

**Part A:**

What is the heaviest the book he can hold vertically before it slips out of his fingers? The coefficient of static friction between his fingers and the book cover is 0.76.

Express your answer in newtons.

\( F_G = \) [Input Box] N

- **Submit** [Button]
- **Request Answer** [Button]
- **Provide Feedback** [Link]

#### Description:

A person with compromised pinch strength in his fingers can exert a force of only 6.0 N to either side of a pinch-held object, such as the book shown in (Figure 1).

**Figure:**

The image illustrates a hand gripping a book using a pinching motion. The grip is shown from the side, with fingers positioned on either side of the book cover.

---

**Instructions for Solving the Problem:**

1. **Understand the Situation:**
   - The person can apply a maximum force of 6.0 N with each finger.
   - The frictional force, which prevents the book from slipping, depends on the normal force (the force applied by the fingers) and the coefficient of static friction.

2. **Apply the Formula for Static Friction:**
   \[
   f_s = \mu_s \times N
   \]
   Where:
   - \( f_s \) is the static friction force.
   - \( \mu_s \) is the coefficient of static friction (0.76).
   - \( N \) is the normal force (equal to the force exerted by the fingers).

3. **Calculate Maximum Weight:**
   - The maximum static friction force is \( 0.76 \times (6.0 \, \text{N} + 6.0 \, \text{N}) \).

4. **Equilibrium Condition:**
   - For equilibrium vertically, the gravitational force (weight of the book) should be equal to the maximum static friction force.

5. **Solve for \( F_G \):**
   - Thus, the heaviest book that can be held is equivalent to this static friction force in newtons.

Use these guidelines to input the value of \( F_G \) in the answer box provided.
Transcribed Image Text:### Educational Exercise on Static Friction #### Problem Statement: **Part A:** What is the heaviest the book he can hold vertically before it slips out of his fingers? The coefficient of static friction between his fingers and the book cover is 0.76. Express your answer in newtons. \( F_G = \) [Input Box] N - **Submit** [Button] - **Request Answer** [Button] - **Provide Feedback** [Link] #### Description: A person with compromised pinch strength in his fingers can exert a force of only 6.0 N to either side of a pinch-held object, such as the book shown in (Figure 1). **Figure:** The image illustrates a hand gripping a book using a pinching motion. The grip is shown from the side, with fingers positioned on either side of the book cover. --- **Instructions for Solving the Problem:** 1. **Understand the Situation:** - The person can apply a maximum force of 6.0 N with each finger. - The frictional force, which prevents the book from slipping, depends on the normal force (the force applied by the fingers) and the coefficient of static friction. 2. **Apply the Formula for Static Friction:** \[ f_s = \mu_s \times N \] Where: - \( f_s \) is the static friction force. - \( \mu_s \) is the coefficient of static friction (0.76). - \( N \) is the normal force (equal to the force exerted by the fingers). 3. **Calculate Maximum Weight:** - The maximum static friction force is \( 0.76 \times (6.0 \, \text{N} + 6.0 \, \text{N}) \). 4. **Equilibrium Condition:** - For equilibrium vertically, the gravitational force (weight of the book) should be equal to the maximum static friction force. 5. **Solve for \( F_G \):** - Thus, the heaviest book that can be held is equivalent to this static friction force in newtons. Use these guidelines to input the value of \( F_G \) in the answer box provided.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Second law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON