A person standing at the edge of a cliff throws a rock upward from a height of 400 ft above ground level with an initial velocity of 46 ft/s. What is the velocity of impact when the rock reaches the bottom of the cliff? Round any intermediate calculations, if needed, to no less than six decimal places, and round your final answer to two decimal places. (Hint: Use h(t) = - 16t² + 46t+ 400 as the position function, where h is in feet, t in seconds. Ignore air resistance.)

University Physics Volume 1
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Chapter2: Vectors
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Problem 2.10CYU: Check Your Understanding Verify that vector v V obtained in Example 2.14 is indeed a unit vector by...
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A person standing at the edge of a cliff throws a rock upward from a height of 400 ft above ground level with an initial velocity of 46 ft/s. What is the velocity of impact
when the rock reaches the bottom of the cliff? Round any intermediate calculations, if needed, to no less than six decimal places, and round your final answer to two
decimal places. (Hint: Use h(t) = 16t² + 46t + 400 as the position function, where his in feet, t in seconds. Ignore air resistance.)
Transcribed Image Text:A person standing at the edge of a cliff throws a rock upward from a height of 400 ft above ground level with an initial velocity of 46 ft/s. What is the velocity of impact when the rock reaches the bottom of the cliff? Round any intermediate calculations, if needed, to no less than six decimal places, and round your final answer to two decimal places. (Hint: Use h(t) = 16t² + 46t + 400 as the position function, where his in feet, t in seconds. Ignore air resistance.)
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