A person standing at the edge of a cliff throws a rock upward from a height of 180 ft above ground level with an initial velocity of 48 ft/s. Calculate the velocity of the rock when it is exactly 32 ft above the person's hand. Separate multiple answers with a comma. (Hint: Use h(t) = - 16t² + 48t + 180 as the position function, where his in feet, t in seconds. Ignore air resistance.)

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