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A person pushes a 12.5 kg lawn mower at constant speed with a force of 82.5 N directed along the handle, which is at an angle of 45.0° to the horizontal. Y Part B Calculate the horizontal friction force on the mower. Express your answer with the appropriate units. μA → Fir = Value Units Submit Request Answer Part C Calculate the normal force exerted vertically upward on the mower by the ground. Express your answer with the appropriate units. 0 μA → ? FN = Value Units Submit Request Answer ?

A person pushes a 12.5 kg lawn mower at constant speed with a force of 82.5 N directed along the handle, which is at an angle of 45.0° to the horizontal. Y Part B Calculate the horizontal friction force on the mower. Express your answer with the appropriate units. μA → Fir = Value Units Submit Request Answer Part C Calculate the normal force exerted vertically upward on the mower by the ground. Express your answer with the appropriate units. 0 μA → ? FN = Value Units Submit Request Answer ?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Assignments #### CH4 HW #### Problem 4.50 A person pushes a 12.5 kg lawn mower at constant speed with a force of 82.5 N directed along the handle, which is at an angle of 45.0° to the horizontal. #### Part B Calculate the horizontal friction force on the mower. **Express your answer with the appropriate units.** Input Box: ``` \[ F_{\text{fr}} = \] ``` Units Input Box: ``` \[\text{Units}\] ``` **Buttons:** - Submit - Request Answer #### Part C Calculate the normal force exerted vertically upward on the mower by the ground. **Express your answer with the appropriate units.** Input Box: ``` \[ F_N = \] ``` Units Input Box: ``` \[\text{Units}\] ``` **Buttons:** - Submit - Request Answer
Transcribed Image Text:### Assignments #### CH4 HW #### Problem 4.50 A person pushes a 12.5 kg lawn mower at constant speed with a force of 82.5 N directed along the handle, which is at an angle of 45.0° to the horizontal. #### Part B Calculate the horizontal friction force on the mower. **Express your answer with the appropriate units.** Input Box: ``` \[ F_{\text{fr}} = \] ``` Units Input Box: ``` \[\text{Units}\] ``` **Buttons:** - Submit - Request Answer #### Part C Calculate the normal force exerted vertically upward on the mower by the ground. **Express your answer with the appropriate units.** Input Box: ``` \[ F_N = \] ``` Units Input Box: ``` \[\text{Units}\] ``` **Buttons:** - Submit - Request Answer
### Physics Problem: Forces Acting on a Pushed Lawn Mower **Problem Description:** A person pushes a 12.5 kg lawn mower at constant speed with a force of 82.5 N directed along the handle, which is at an angle of 45.0° to the horizontal. **Instructions:** Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. **Required Vectors:** 1. **Force of Gravity (\( \vec{F}_g \))**: The force of gravity acting on the lawn mower. 2. **Friction Force (\( \vec{F}_r \))**: The force of friction opposing the motion of the lawn mower. 3. **Normal Force (\( \vec{F}_N \))**: The perpendicular contact force exerted by the ground on the lawn mower. **Diagram Explanation:** The image provided shows a person pushing a lawn mower. The force applied (\( \vec{F} \)) is represented by a vector along the handle at a 45° angle to the horizontal. The position of where the vectors should be drawn originates from a black dot: 1. **Force of Gravity (\( \vec{F}_g \))**: This vector points downward, representing the gravitational force acting on the 12.5 kg lawn mower. 2. **Friction Force (\( \vec{F}_r \))**: This vector typically points in the opposite direction of the motion, parallel to the surface. 3. **Normal Force (\( \vec{F}_N \))**: This vector points perpendicular to the ground, representing the support force exerted by the ground on the lawn mower. **Concepts to Consider:** - **Newton's First Law** (Law of Inertia): Since the mower is moving at a constant speed, the net force acting on it must be zero. - **Components of Forces**: When decomposing forces into horizontal and vertical components, use trigonometric functions to find the respective components along the axes. **Calculation Tips:** 1. **Force of Gravity (\( \vec{F}_g \))**: Calculate using \( F_g = m \cdot g \), where \( m \) is the mass (12.5 kg) and \( g \) is the acceleration due to gravity (9.8 m/s²). 2. **Normal
Transcribed Image Text:### Physics Problem: Forces Acting on a Pushed Lawn Mower **Problem Description:** A person pushes a 12.5 kg lawn mower at constant speed with a force of 82.5 N directed along the handle, which is at an angle of 45.0° to the horizontal. **Instructions:** Draw the vectors starting at the black dot. The location and orientation of the vectors will be graded. **Required Vectors:** 1. **Force of Gravity (\( \vec{F}_g \))**: The force of gravity acting on the lawn mower. 2. **Friction Force (\( \vec{F}_r \))**: The force of friction opposing the motion of the lawn mower. 3. **Normal Force (\( \vec{F}_N \))**: The perpendicular contact force exerted by the ground on the lawn mower. **Diagram Explanation:** The image provided shows a person pushing a lawn mower. The force applied (\( \vec{F} \)) is represented by a vector along the handle at a 45° angle to the horizontal. The position of where the vectors should be drawn originates from a black dot: 1. **Force of Gravity (\( \vec{F}_g \))**: This vector points downward, representing the gravitational force acting on the 12.5 kg lawn mower. 2. **Friction Force (\( \vec{F}_r \))**: This vector typically points in the opposite direction of the motion, parallel to the surface. 3. **Normal Force (\( \vec{F}_N \))**: This vector points perpendicular to the ground, representing the support force exerted by the ground on the lawn mower. **Concepts to Consider:** - **Newton's First Law** (Law of Inertia): Since the mower is moving at a constant speed, the net force acting on it must be zero. - **Components of Forces**: When decomposing forces into horizontal and vertical components, use trigonometric functions to find the respective components along the axes. **Calculation Tips:** 1. **Force of Gravity (\( \vec{F}_g \))**: Calculate using \( F_g = m \cdot g \), where \( m \) is the mass (12.5 kg) and \( g \) is the acceleration due to gravity (9.8 m/s²). 2. **Normal
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