A person leans over a cliff that is 2000 feet high and throws a rock vertically upward at a speed of 100 ft/sec. When it falls, it barely misses the cliff and falls on the ground at the base of the cliff. The height of the rock (in feet) above the ground t seconds after it was thrown is given by the function f(t) = -16^2 + v0t + s0 where v0 is the initial velocity of the rock and so is the original height of the rock. Therefore f(t)=-16t^2+100t+2000. Determine when the rock will hit the ground at the base of the cliff. What was the maximum height of the rock?

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