A person is accelerating a box across the floor using a force Fpull for a distance d. There is a force of friction on the box Ff. How would you expect the amount of net work done in the x-direction (Wnet) to compare to Wpull, the amount of work done by the pulling force? Wnet = Wpull because Wpull is calculated using the net force Wnet < Wpull because the friction force does negative work Wnet > Wpull because the friction force also does work Wnet = 0 because the pulling force and the friction force cancel out
A person is accelerating a box across the floor using a force Fpull for a distance d. There is a force of friction on the box Ff. How would you expect the amount of net work done in the x-direction (Wnet) to compare to Wpull, the amount of work done by the pulling force? Wnet = Wpull because Wpull is calculated using the net force Wnet < Wpull because the friction force does negative work Wnet > Wpull because the friction force also does work Wnet = 0 because the pulling force and the friction force cancel out
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A person is accelerating a box across the floor using a force Fpull for a distance d. There is a force of friction on the box
Ff. How would you expect the amount of net work done in the x-direction (Wnet) to compare to Wpull, the amount of
work done by the pulling force?
Wnet = Wpull because Wpull is calculated using the net force
Wnet < Wpull because the friction force does negative work
Wnet > Wpull because the friction force also does work
Wnet = 0 because the pulling force and the friction force cancel out
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