A person consumes about 2800 Cal a day. 1 Cal=4186 J, and 1 kWh 860 Cal. ▸ Part B Part C If a power company charges about 12 e per kilowatt-hour, how much would this energy cost per day if the person bought it from the power company? Express your answer using two significant figures. ΑΣΦ | X √x √xx 4 → 1X1 X-10° 401 ? Cost 39 You have already submitted this answer. Enter a new answer No credit lost. Try again $ per day

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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A person consumes about 2800 Cal a day.
1 Cal-4186 J, and 1 kWh-860 Cal.
Part B
Part C
If a power company charges about 12 e per kilowatt-hour, how much would this energy cost per
day if the person bought it from the power company?
Express your answer using two significant figures.
195] ΑΣΦΑ
X"
X
4 →
√ √xx X LXI
Ed ?
X-10°
401
Cost 39
You have already submitted this answer. Enter a new answer.
No credit lost. Try again
[20]
$ per day
Transcribed Image Text:A person consumes about 2800 Cal a day. 1 Cal-4186 J, and 1 kWh-860 Cal. Part B Part C If a power company charges about 12 e per kilowatt-hour, how much would this energy cost per day if the person bought it from the power company? Express your answer using two significant figures. 195] ΑΣΦΑ X" X 4 → √ √xx X LXI Ed ? X-10° 401 Cost 39 You have already submitted this answer. Enter a new answer. No credit lost. Try again [20] $ per day
An insulated beaker with negligible mass contains liquid water with a mass of 0.330 kg and a
temperature of 60.5 °C.
Part A
How much ice at a temperature of -18.5 °C must be dropped into the water so that the final
temperature of the system will be 40.0 °C?
Take the specific heat of liquid water to be 4190 J/kg K, the specific heat of ice to be 2100
J/kg K, and the heat of fusion for water to be 3.34x105 J/kg.
Transcribed Image Text:An insulated beaker with negligible mass contains liquid water with a mass of 0.330 kg and a temperature of 60.5 °C. Part A How much ice at a temperature of -18.5 °C must be dropped into the water so that the final temperature of the system will be 40.0 °C? Take the specific heat of liquid water to be 4190 J/kg K, the specific heat of ice to be 2100 J/kg K, and the heat of fusion for water to be 3.34x105 J/kg.
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