A perfectly elastic ball bounces against a surface with a velocity vo = 2.4 m/s at an angle 0o = 45 degrees to the vertical. As a result of the impact, theball bounces upward at an angle 0₁ = 23.2 degrees but also gains a topspin w₁ = 152 rad/s due to the rough surface. The ball has mass m = 10 gramsand radius R = 16 mm. The moment of inertia of a solid sphere is /G = (2 m R²) / 5. The coefficient of restitution for the impact e = 1, so that energy canbe assumed to be conserved during impact.gW₁ = 0Vo0₁W₁Calculate the magnitude of the velocity v₁ of the ball after impact.Ov=2.85 m/sO V = 2.4 m/sO V = 1.84 m/sO V = 1.67 m/sV₁

To solve this problem, we can apply the principle of conservation of mechanical energy. We can…

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