A patient recovering from surgery is being given fluid intravenously. The fluid has a density of 1080 kg/m³, and 6.61 x 10-4 m³ of it flows into the patient every 8 hours. Find the mass flow rate in kg/s.
A patient recovering from surgery is being given fluid intravenously. The fluid has a density of 1080 kg/m³, and 6.61 x 10-4 m³ of it flows into the patient every 8 hours. Find the mass flow rate in kg/s.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![**Problem Statement: Mass Flow Rate Calculation**
A patient recovering from surgery is being given fluid intravenously. The fluid has a density of 1080 kg/m³, and 6.61 x 10⁻⁴ m³ of it flows into the patient every 8 hours. Find the mass flow rate in kg/s.
**Solution:**
To find the mass flow rate, we will use the formula:
\[ \text{Mass Flow Rate} = \frac{\text{Density} \times \text{Volume Flow Rate}}{\text{Time}} \]
Given data:
- Density (\( \rho \)): 1080 kg/m³
- Volume (\( V \)): 6.61 x 10⁻⁴ m³
- Time (\( t \)): 8 hours
First, convert the time from hours to seconds:
\[ 8 \text{ hours} = 8 \times 3600 \text{ seconds} = 28,800 \text{ seconds} \]
Now, calculate the volume flow rate (\( \dot{V} \)):
\[ \dot{V} = \frac{V}{t} = \frac{6.61 \times 10⁻⁴ \text{ m³}}{28,800 \text{ s}} \]
Calculate the mass flow rate (\( \dot{m} \)):
\[ \dot{m} = \rho \times \dot{V} = 1080 \text{ kg/m³} \times \left( \frac{6.61 \times 10⁻⁴ \text{ m³}}{28,800 \text{ s}} \right) \]
Perform the calculations:
\[ \dot{V} = \frac{6.61 \times 10⁻⁴}{28,800} = 2.294097 \times 10⁻⁸ \text{ m³/s} \]
\[ \dot{m} = 1080 \text{ kg/m³} \times 2.294097 \times 10⁻⁸ \text{ m³/s} = 2.478445 \times 10⁻⁵ \text{ kg/s} \]
Therefore, the mass flow rate is approximately:
\[ 2.48 \times 10⁻⁵ \text{ kg/s} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70495d9e-d834-4a3c-919e-f23d4c42494e%2F3d6a8194-8e06-45ec-8e9f-39c0a145fa9e%2Fhkrgyb9_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement: Mass Flow Rate Calculation**
A patient recovering from surgery is being given fluid intravenously. The fluid has a density of 1080 kg/m³, and 6.61 x 10⁻⁴ m³ of it flows into the patient every 8 hours. Find the mass flow rate in kg/s.
**Solution:**
To find the mass flow rate, we will use the formula:
\[ \text{Mass Flow Rate} = \frac{\text{Density} \times \text{Volume Flow Rate}}{\text{Time}} \]
Given data:
- Density (\( \rho \)): 1080 kg/m³
- Volume (\( V \)): 6.61 x 10⁻⁴ m³
- Time (\( t \)): 8 hours
First, convert the time from hours to seconds:
\[ 8 \text{ hours} = 8 \times 3600 \text{ seconds} = 28,800 \text{ seconds} \]
Now, calculate the volume flow rate (\( \dot{V} \)):
\[ \dot{V} = \frac{V}{t} = \frac{6.61 \times 10⁻⁴ \text{ m³}}{28,800 \text{ s}} \]
Calculate the mass flow rate (\( \dot{m} \)):
\[ \dot{m} = \rho \times \dot{V} = 1080 \text{ kg/m³} \times \left( \frac{6.61 \times 10⁻⁴ \text{ m³}}{28,800 \text{ s}} \right) \]
Perform the calculations:
\[ \dot{V} = \frac{6.61 \times 10⁻⁴}{28,800} = 2.294097 \times 10⁻⁸ \text{ m³/s} \]
\[ \dot{m} = 1080 \text{ kg/m³} \times 2.294097 \times 10⁻⁸ \text{ m³/s} = 2.478445 \times 10⁻⁵ \text{ kg/s} \]
Therefore, the mass flow rate is approximately:
\[ 2.48 \times 10⁻⁵ \text{ kg/s} \]
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