A particular 1 3 a. b. C. d. e. solution of y" + 2y'-3y = 1 + xex. 1 3 1 1 2 --xx + 1x2²ex 3 8 8 3 -1/33 1 | M | M xex+ 2 --xx-x²ex 8 1 16 1 16 −13+ ·x² ex 3 -xex + 1x² e 2 ex -xex + 1x² ex

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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### A particular solution of \( y'' + 2y' - 3y = 1 + xe^x \).

#### Options:
**a.** 
\[
\frac{1}{3} - \frac{1}{4} xe^x + \frac{3}{4} x^2 e^x
\]

**b.** 
\[
-\frac{1}{3} - \frac{2}{8} xe^x + \frac{1}{8} x^2 e^x
\]

**c.** 
\[
-\frac{1}{3} - \frac{2}{8} xe^x - \frac{3}{8} x^2 e^x
\]

**d.** 
\[
-\frac{1}{3} - \frac{1}{16} xe^x + \frac{1}{8} x^2 e^x
\]

**e.** 
\[
-\frac{1}{3} + \frac{1}{16} xe^x + \frac{1}{8} x^2 e^x
\]

### Explanation:
In this problem, you are asked to identify the particular solution to the non-homogeneous linear differential equation \( y'' + 2y' - 3y = 1 + xe^x \). 

#### Breakdown of Options:
- Each option represents a different candidate for the particular solution of the differential equation.
- The terms in each option involve combinations of constants, exponential functions \(e^x\), and their products with \(x\) and \(x^2\).

For educational synthesis:
- **Constants**: The constants could represent specific values that arise from the solution process.
- **Exponential Terms**: The terms involving \( xe^x \) and \( x^2e^x \) suggest the use of the method of undetermined coefficients to account for the non-homogeneous term on the right-hand side of the equation \( 1 + xe^x \).

Understanding which particular solution correctly satisfies the given differential equation is often achieved through substitution and verification.

**Step-by-step approach**:
1. **Assumption**: Assume a particular form based on the non-homogeneous term.
2. **Substitute**: Substitute this assumed form into the differential equation.
3. **Solve for coefficients**: Balance the equation by solving for unknown
Transcribed Image Text:### A particular solution of \( y'' + 2y' - 3y = 1 + xe^x \). #### Options: **a.** \[ \frac{1}{3} - \frac{1}{4} xe^x + \frac{3}{4} x^2 e^x \] **b.** \[ -\frac{1}{3} - \frac{2}{8} xe^x + \frac{1}{8} x^2 e^x \] **c.** \[ -\frac{1}{3} - \frac{2}{8} xe^x - \frac{3}{8} x^2 e^x \] **d.** \[ -\frac{1}{3} - \frac{1}{16} xe^x + \frac{1}{8} x^2 e^x \] **e.** \[ -\frac{1}{3} + \frac{1}{16} xe^x + \frac{1}{8} x^2 e^x \] ### Explanation: In this problem, you are asked to identify the particular solution to the non-homogeneous linear differential equation \( y'' + 2y' - 3y = 1 + xe^x \). #### Breakdown of Options: - Each option represents a different candidate for the particular solution of the differential equation. - The terms in each option involve combinations of constants, exponential functions \(e^x\), and their products with \(x\) and \(x^2\). For educational synthesis: - **Constants**: The constants could represent specific values that arise from the solution process. - **Exponential Terms**: The terms involving \( xe^x \) and \( x^2e^x \) suggest the use of the method of undetermined coefficients to account for the non-homogeneous term on the right-hand side of the equation \( 1 + xe^x \). Understanding which particular solution correctly satisfies the given differential equation is often achieved through substitution and verification. **Step-by-step approach**: 1. **Assumption**: Assume a particular form based on the non-homogeneous term. 2. **Substitute**: Substitute this assumed form into the differential equation. 3. **Solve for coefficients**: Balance the equation by solving for unknown
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