A particle with charge 1.60 × 10-19 C enters midway between two charged plates, one positive and the other negative. The initial velocity of the particle is parallel to the plates and along the midline between them (see figure below). A potential difference of 130.0 V is maintained between the two charged plates. If the lengths of the plates are 10.0 cm and they are separated by 2.00 cm, find the greatest initial velocity for which the particle will not be able to exit the region between the plates. The mass of the particle is 21.0 x 10-24 kg. (Enter the magnitude.) m/s 10.0 cm + + + + + m 2.00 cm

icon
Related questions
Question

Please read the question and leave notes on the answer where appropriate. Please DO NOT skip any steps. Please double check your answer. Please do not type out a response. Please use LaTeX or use a hand written response that is LEGABLE. Please review your answer to make sure all steps are clearly visable. Please double check your work. Thank you. 

A particle with charge 1.60 x 10-19 C enters midway between two charged plates, one positive and the other
negative. The initial velocity of the particle is parallel to the plates and along the midline between them (see figure
below). A potential difference of 130.0 V is maintained between the two charged plates. If the lengths of the plates
are 10.0 cm and they are separated by 2.00 cm, find the greatest initial velocity for which the particle will not be
able to exit the region between the plates. The mass of the particle is 21.0 x 10-24 kg. (Enter the magnitude.)
m/s
10.0 cm
+
+
+
m
2.00 cm
Transcribed Image Text:A particle with charge 1.60 x 10-19 C enters midway between two charged plates, one positive and the other negative. The initial velocity of the particle is parallel to the plates and along the midline between them (see figure below). A potential difference of 130.0 V is maintained between the two charged plates. If the lengths of the plates are 10.0 cm and they are separated by 2.00 cm, find the greatest initial velocity for which the particle will not be able to exit the region between the plates. The mass of the particle is 21.0 x 10-24 kg. (Enter the magnitude.) m/s 10.0 cm + + + m 2.00 cm
Expert Solution
Given

Given:

Charge,q=1.6×10-19CPotential Difference,V=130VLength,L=10cm=10×10-2mSeperated Distance,d=2cm=2×10-2mMass of the particle,m=21×10-24kgInitial Velocity in y-component,u=0m/s

A charge near its surroundings produces an electric field, which is a force. When other charges are brought near this field, they are subjected to this force. The force that a unit positive charge would experience if placed at that point is called the electric field due to a charge at a point.

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer