A particle with a charge of +4.20 nC is in a uniform electric field /E directed to the negative x direction. It is released from rest, and after it has moved 5.00 cm, its kinetic energy is found to be 1.50x10-6 J. What work was done by the electric force?What was the change in electric potential over the distance that the charge moved?What is the magnitude of –→/E?What was the change in potential energy of the charge?
A particle with a charge of +4.20 nC is in a uniform electric field /E directed to the negative x direction. It is released from rest, and after it has moved 5.00 cm, its kinetic energy is found to be 1.50x10-6 J. What work was done by the electric force?What was the change in electric potential over the distance that the charge moved?What is the magnitude of –→/E?What was the change in potential energy of the charge?
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A particle with a charge of +4.20 nC is in a uniform electric field /E directed to the negative x
direction. It is released from rest, and after it has moved 5.00 cm, its kinetic energy is found to be
1.50x10 6 J.
What work was done by the electric force?What was the change in electric potential over the distance
that the charge moved?What is the magnitude of /E?What was the change in potential energy of the
charge?
Expert Solution
Concept
The work done by the electric force is given by
Where q = Charge of the particle, ΔV = Change in electric potential, ΔKE = Change in kinetic energy, ΔU = Change in potential energy
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